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dolphi86 [110]
3 years ago
15

I have been stuck on this forever. Please help me

Mathematics
1 answer:
il63 [147K]3 years ago
5 0
2a. speed= distance
---------------
time

60÷69 = 52.1739 miles per hour.



so for the next one with the airplane flies 296 km in 276 min is the same formula.
296/276 = 39.9839 mph.

I couldn't see the first question clear...sorry but apply same formula.
Hoping this will help you
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657000 in standard form
valkas [14]

6.57000 and in the expontent is how many times u move the decimal up :> hope  i helped

7 0
3 years ago
The equation y = 5x +7 models the number of Beanie Babies (y) that Mr. Crawford owns each month(x).
ddd [48]
After 42 months he will own 217 beanie babies

Take 217 and subtract 7 from it

217-7=210

Then you want to divide that number by 5

210/5=42

You can always fill in 42 for x and you will get 217 as your answer

5 x 42 =210 + 7= 217
3 0
3 years ago
Read 2 more answers
The ordered pairs (6,8), (9, 12), (x, 20), (18, y) represent a proportional relationship. Find the value of X and the value of Y
sasho [114]

Answer:

x=15 y=24

Step-by-step explanation:

This is because the rule is x goes up 3 y goes up 4

(9,12)->(x,20)

it skips one, so instead of adding 3 we add six

x=15

(15,20)->(18,y)

you follow the rule and 4.

Y=24

7 0
3 years ago
Question below
Ksivusya [100]

Answer:

m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right]

Step-by-step explanation:

<u>Calculate the value of m</u>

Given:

3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]

Therefore:

\implies 3=\dfrac{2}{3}m

\implies m=3 \times \dfrac{3}{2}

\implies m=\dfrac{9}{2}

<u>Calculate the value of H</u>

Given:

\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)

Therefore:

\implies H= \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]

<u />

<u>Calculating m × H</u>

<u />

<u />\implies m \times H=\dfrac{9}{2} \times \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]

<u />\implies m \times H=\left[\begin{array}{c c c}\dfrac{9}{2}(-2) & \dfrac{9}{2}(8) & \dfrac{9}{2}(-1)\end{array}\right]

\implies m \times H=\left[\begin{array}{c c c}-9 & 36 & -\dfrac{9}{2}\end{array}\right]<u />

7 0
1 year ago
Graph the equation Y =x2+2x - 3
mr_godi [17]

Answer:

Plot the following and connect the dots:

y-intercept: (0, -3)

x-intercepts: (1, 0) and (-3, 0)

vertex: (-1, -4)

Step-by-step explanation:

To graph an equation, you need some points that are on the graph.

y = x² + 2x - 3

This equation is given in standard form, y = ax² + bx + c.

"c" is the <u>y-intercept</u>, where the graph hits the y-axis.

Since c = -3, one point is:

<h3>(0, -3)</h3>

a = 1; b = 2; c = -3

y = x² + 2x - 3

Since a = 1, we can factor by breaking down "b".

Find two numbers that add to get "b", and also multiply to get "c".

? + ? = 2

? × ? = -3

Try 3 and -1:

3 + -1 = 2                Correct

3 × -1 = -3               Correct

Split the "b" value into p and q. <u>Use group factoring</u>.

y = x² - x + 3x - 3

Group terms that looks alike.

y = (x² - x) + (3x - 3)

Collect another pair of like terms.

y = x(x - 1) + 3(x - 1)

y = (x - 1)(x + 3)                      This is fully factored. Use this to <u>find the roots</u>.

<u>The roots are the x-intercepts, when y = 0</u>.

0 = (x - 1)(x + 3)

Split the factors and equate them to 0.

0 = x - 1            0 = x + 3

x = 1                   x = -3

<h3>(1, 0)             (-3, 0)</h3>

We also need the vertex. Use <u>complete the square</u>.

y = x² + 2x - 3

y = (x² + 2x) - 3           Divide the "b" term by 2, and square. (2/2)² = 1

y = (x² + 2x + 1 - 1) - 3              Add and subtract 1.

y = (x² + 2x + 1) - 1 - 3              Take out the negative.

y = (x² + 2x + 1) - 4               Simplify

Now <u>factor the bracketed expression</u>, just like before.

x² + 2x + 1

? + ? = 2

? × ? = 1

Try 1 and 1:

1 + 1 = 2

1 × 1 = 1

The factored expression is: (x + 1)(x + 1) = (x + 1)²

Put it back into the equation for the graph:

y = (x + 1)² - 4

This is vertex form: y = a(x - h)² + k, where the vertex is (h, k).

<h3>(-1, -4)</h3><h3 />

See the graph below, the blue is the plotted points.

3 0
3 years ago
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