Question

Given that P = (5, 8) and Q = (6, 9), find the component form and magnitude of vector PQ.

Answer 1

((x2-x1),(y2-y1))
((6-5),(9-8))
Component form: (1,1)
(1^2+1^2)^(1/2)
Magnitude: (2)^(1/2)

Answer 2

Answer:

Step-by-step explanation:

Given : P = (5, 8) and Q = (6, 9)

To find: the component form and magnitude of vector PQ.

Solution: It is given that P = (5, 8) and Q = (6, 9).

The component form of the vector PQ is given as:

$Vector PQ=Q-P$

$Vector PQ=$

$Vector PQ=$

The magnitude of vector PQ is given as:

$||=\sqrt{x^2+y^2}$

$||=\sqrt{(1)^2+(1)^2}$

$||=\sqrt{2}$

$||=1.414$

Thus, the component form of the vector PQ is $Vector PQ=$ and the magnitude form is $||=1.414$.