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olga_2 [115]
3 years ago
12

a private jet can fly 1,210 miles against the headwind in the same amount of time it can fly 1,694 miles with a 25 mph tailwind.

find the speed of the jet
Mathematics
2 answers:
BigorU [14]3 years ago
4 0

Let us assume speed of the Jet = x mph.

We are given speed of wind = 25 mph.

Total speed of the Jet with tailwind = (x+25) mph.

Total speed of the Jet with headwind = (x-25) mph.

We know, relation among time, rate and time is given by formula:

Time = Distance/Speed.

<h3>Time taken against the headwind = 1210/(x-25).</h3><h3>Time taken against the tailwind = 1694/(x+25).</h3>

Both times are same.

Therefore,

<h3>1210/(x-25) = 1694/(x+25)</h3>

On cross multiplying, we get

1210(x+25) = 1694(x-25)

1210x + 30250 = 1694x - 42350.

Adding 42350 on both sides,

1210x + 30250+42350 = 1694x - 42350 + 42350.

1210x +72600 = 1694x

Subtracting 1210x from both sides, we get

1210x-1210x +72600 = 1694x -1210x

72600 = 484x.

Dividing both sides by 484, we get

72600/484 = 484x/484.

<h3>150 =x.</h3><h3>Therefore, the speed of the Jet is 150 mph..</h3>
Lorico [155]3 years ago
4 0

Answer:

Step-by-step explanation:

Vhjj

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