Ask question

Ask question

All categories

3 years ago

11

Write a numerical expression to match the word expression. four less than one-fourth of the product of ten thirds and six ✓ ✗ (

10 3 × 6) − 6 × 1 4 10 3 4

1 answer:

RSB [31]3 years ago

8 0

<span>product of ten thirds and six
10/3 x 6

</span><span>one-fourth of ....
1/4 (10/3 x 6)

</span><span> four less than ....
</span>1/4 (10/3 x 6) - 4

You might be interested in

Two factory plants are making tv panels. Plant A produced 2000 fewer panels than Plan B did. Two percent of the panels from Plan

Serggg [28]

Answer:

Plant A produced 15,000 panels.

Step-by-step explanation:

Let plant B produce x panels

Plant A then produced x - 2000 panels

2% of panels from plant A were defective

3% of panels from plant B were defective

The two plants together produced 810 defective panels so;

2/100(x - 2000) + 3/100(x) = 810

0.02x - 40 + 0.03x = 810

0.05x = 850

x = 17,000 panels

So plant B produced 17,000 panels

Plant A produced 17,000 - 2,000 panels = 15,000 panels.

8 0

3 years ago

The pie chart below illustrates the future plans of 200members of St.Thomas graduating class.

ruslelena [56]

Answer:

<h2>a) approximately 133 graduates</h2><h2>b) approximately 120°</h2>

Step-by-step explanation:

a) the number of graduates planning to continue studying :

= (37 1/2% + 12 1/2% + 16 2/3%) × 200

$=\frac{\left( 37\frac{1}{2} +12\frac{1}{2} +16\frac{2}{3} \right) }{100} \times200$

= (37.5 + 12.5 + 16.666666666667)×2

= 133.333333333334

…………………………………

b) the measurement of the angle representing those who plan to work :

= (360× 33 1/2)÷100

= (360× 33.333333333333)÷100

=119.999999999999

8 0

2 years ago

The sum of an integer and 7 more than the next consecutive integer is 66. find the integer

Cloud [144]

If the sum of an integer and 7 more than the next consecutive integer is 66 then the integers are 29 and 30.

Given that the sum of an integer and 7 more than the next consecutive integer is 66.

Integer is a number that is written without a fraction component. It can be positive as well as negative.

let the first integer be x.

Consecutive integer will be x+1.

Sum of integer and 7 more than the next consecutive integer is 66.

Sum according to the given information=x+x+1+7

=2x+8

2x+8=66

2x=66-8

2x=58

x=58/2

x=29

Next integer=29+1-30.

Hence if the sum of an integer and 7 more than the next consecutive integer is 66 then the integers are 29 and 30.

Learn more about integers at brainly.com/question/17695139

#SPJ4

8 0

2 years ago

Abigail shows up at a restaurant that has 30 tables 12 of them are booth and 18 of them are tables with chairs what is the proba

elixir [45]

30 divided by 12 will give you the percentage 40% , or c

8 0

3 years ago

Read 2 more answers

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(U |D ) = 0.198$

b

$P(O\ n \ B) = 0.188$

c

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

=>

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

=>

So

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

So

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

So

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago