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ElenaW [278]
3 years ago
5

8 over negative 4 ÷ negative 3 over 9.

Mathematics
2 answers:
gavmur [86]3 years ago
8 0
-8/4 divided by -3/9 equals 6
yaroslaw [1]3 years ago
3 0
I'd prefer you write this out symbolically instead of in words:

   8                       -3
------- divided by -----
   -4                        9

Why not reduce both fractions first?  We get    -2   divided by -1/3, which is
the same as -2 times -3.  Answer:   6


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Which of the following quadratic solutions has the following solution
castortr0y [4]

Answer:

The first and second one

Step-by-step explanation:

plug in x :)

4 0
3 years ago
Item 16 The variables x and y vary directly. Use the values to find the constant of proportionality, k. Then write an equation t
masya89 [10]

Answer:

k = 2

x = 2y

Step-by-step explanation:

If variables x and y vary directly, this is expressed as;

x ∝ y

x = ky

k is the proportionality constant

Let's assume the value of x and y since we are not given;

x = 20

y = 10

Substitute

20 = k(10)

10k = 20

k = 20/10

k = 2

Hence the constant of proportionality is 2

Substitute i=k = 2 into the equation x = ky

x = 2y

Hence an equation that relates x and y is x = 2y

<em>Note that the values here are assumed value, you can use the same method for any values of x and y</em>

4 0
3 years ago
F(x)=2x^2-x-10 part a: what are the X intercepts of the graph of f(x)? Show your work
Genrish500 [490]
A. x intercepts are where the graph hits the x axis or where f(x)=0
0=2x^2-x-10
solve
hmm
we can use the ac method
multiply 2 and -10 to get -20
what 2 numbers muliply to get -20 and add to get -1 (the coefint of the x term)
-5 and 4
split the midd into that
0=2x^2+4x-5x-10
group
0=(2x^2+4x)+(-5x-10)
factor
0=2x(x+2)-5(x+2)
undistribute
0=(x+2)(2x-5)
set each to 0
0=x+2
0=-2

0=2x-5
5=2x
5/2=x

x intercepts are at x=-2 and 5/2 or the points (-2,0) and (5/2,0)


B. ok, so for f(x)=ax^2+bx+c
if a>0, then the parabola opens up and the vertex is a minimum
if a<0 then the parabola opens down and the vertex is a max

f(x)=2x^2-x-10
2>0
opoens up
vertex is minimum

ok, the vertex

the x value of  the vertex in f(x)=ax^2+bx+c= is -b/(2a)
the y value of the vertex is f(-b/(2a)) so
given
f(x)=2x^2-x-10
a=2
b=-1
-b/2a=-(-1)/(2*2)=1/4
f(1/4)=2(1/4)^2-(1/4)-10
f(1/4)=2(1/16)-1/4-10
f(1/4)=1/8-1/4-10
f(1/4)=1/8-2/8-80/8
f(1/4)=-81/8
so the vertex is (1/4,-81/8) or (0.25,-10.125)


C. graph the x intercepts and the vertex
the vertex is min and the graph goes through the x intercepts
4 0
3 years ago
Pleaseeee helpp answer correctly !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!
Pavel [41]

Answer:

x = 87º

Step-by-step explanation:

opposing angles in quadrilaterals are equal, so x = 87º

5 0
3 years ago
Read 2 more answers
What is the horizontal shift for the graph of f(x) = (x - 3)3 + 2? A. Left 2 B. Right 2 C. Left 3 D. Right 3
jarptica [38.1K]
The graph of the function f(x) = (x - 3)^3 + 2 is 3 units to the right of the parent function.
Hence the horizontal shift is right 3.
3 0
3 years ago
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