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2 years ago

5

8 over negative 4 ÷ negative 3 over 9.

2 answers:

gavmur [86]2 years ago

8 0

-8/4 divided by -3/9 equals 6

yaroslaw [1]2 years ago

3 0

I'd prefer you write this out symbolically instead of in words:

8 -3
------- divided by -----
-4 9

Why not reduce both fractions first? We get -2 divided by -1/3, which is
the same as -2 times -3. Answer: 6

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2 years ago

NEED HELP ASAP<br> Given G (-6,5) and H (2, -7), what is the length of GH

lesya692 [45]

$\bold{\huge{\green{\underline{ Solution }}}}$

$\bold{\underline{ Given}}$

<u>We </u><u>have </u><u>given </u><u>that </u><u>the </u><u>coordinates </u><u>of </u><u>the </u><u>end </u><u>point </u><u>G </u><u>and </u><u>H </u><u>are </u><u>(</u><u> </u><u>-</u><u>6</u><u>,</u><u>5</u><u>)</u><u> </u><u>and </u><u>(</u><u> </u><u>2</u><u>,</u><u> </u><u>-</u><u>7</u><u> </u><u>)</u>

$\bold{\underline{To \: Find :- }}$

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>length </u><u>of </u><u>GH </u>

$\bold{\underline{Let's \: Begin :- }}$

The coordinates of G = ( -6 , 5 )

The coordinates of H = ( 2 , - 7 )

<u>According </u><u>to </u><u>the </u><u>distance </u><u>formula</u><u>, </u><u> </u><u>we </u><u>get </u><u>:</u><u>-</u><u> </u>

$\purple{\bigstar}\boxed{\sf{Distance\:\:GH=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2\;}}}$

<u>Here</u><u>, </u><u> </u><u>x1</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>,</u><u> </u><u>x2</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>and </u><u>y1</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>,</u><u> </u><u>y2</u><u> </u><u>=</u><u> </u><u>-</u><u>7</u>

<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u>

$\sf{ Distance \:GH = √( -6 - 2)² + ( 5 -(-7))²}$

$\sf{Distance\:GH= √(-8)^2+(5 + 7)^2}$

$\sf{Distance\:GH=√(-8)^2+(12)^2}$

$\sf{ Distance \:GH =√64 + 144 }$

$\sf{ Distance \:GH =√ 208}$

$\sf{ Distance\: GH = √ 2 × 2 × 2 × 2 × 13}$

$\sf{ Distance \:GH = 4√13}$

$\sf{\red{ Hence\: the \: length\:of \: GH \: is \: 4√13 \: units}}$

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2 years ago