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3 years ago

I need some help plz???

Mathematics

1 answer:

GaryK [48]3 years ago

6 0

I think the ones that would apply to this would be a. b. and c.

Since they are on the same line the slope doesn't change!

Hope I helped :)

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What is the answer to this problem -2x – 4 < 3x + 21

horsena [70]

Start with

$-2x-4 < 3x+21$

Add 2x to both sides:

$-4 < 5x+21$

Subtract 21 from both sides:

$-25 < 5x$

Divide both sides by 5. Since it is positive, we don't have to change the inequality sign:

$-5 < x$

So, the answer is $x > -5$

6 0

2 years ago

Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap

pantera1 [17]

Answer:

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e $\dfrac{dV}{dt}= 20 \ ft^3/min$

we know that radius r is always twice the diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

$V = \dfrac{\pi r^2 h}{3}$

$V = \dfrac{\pi (h/2)^2 h}{3}$

$V = \dfrac{1}{12} \pi h^3$

$V = \dfrac{ \pi h^3}{12}$

Taking the differentiation of volume V with respect to time t; we have:

$\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}$

$\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}$

we know that:

$\dfrac{dV}{dt}= 20 \ ft^3/min$

So;we have:

$20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}$

$20= 56.25 \pi \times \dfrac{dh}{dt}$

$\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

8 0

3 years ago

If a scale distance of 3.5 inches on a map represent an actual distance of 175 km what actual distance does a scale distance of

gavmur [86]

Considering the definition of map and scale, an actual distance of 269.59 km represent a scale distance of 5.7 inches .

<h3>Definition of map and scale</h3>

A map is a representation of a place, at a size smaller than the real size.

The scale of a cartographic representation is the relationship of similarity between the real dimensions of the geographical space represented and those of its image on the map. That is, the scale is defined as the proportionality relationship that exists between a distance measured on the ground and its corresponding measurement on the map.

One way to represent the scale is by a fraction, which indicates the proportion between the distance on a map and its corresponding distance in reality:

$Scale=\frac{distance on the map}{distance in reality}$

<h3>Actual distance in this case</h3>

In this case, you know that a scale distance of 3.5 inches on a map represent an actual distance of 175 km.

To know the real distance that represents a scale distance of 5.7 inches, as the scale ratio is the same as in the previous case, it is expressed:

$\frac{3.7 inches}{175 km}=\frac{5.7 inches}{distance in reality}$