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Liula [17]
3 years ago
5

one pipe can fill a pool 1.25x faster than the second pipe. when both pipes are open they fill the pool in 5 hours. how long wou

ld it take to fill the pool if only the slower is used?
Mathematics
1 answer:
Setler [38]3 years ago
6 0
Suppose the bigger time fills up the pool in x hours, the smaller pipe fills up the pool in 1.25x. 
each hour the pipe finishes 1/x portion of the job, and the smaller pipe finishes 1/1.25x portion
in 5 hours, with both pipe working, the pool is full, that is 5/x + 5/1.25x =1
5/x +4/x=1
x=9
1.25*9=11.25=11 and a quarter=11 hours and 15 minutes
it will take the slower pipe 11 hours and 15 minutes to fill up the pool. 
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Varvara68 [4.7K]

Answer:

 Option A is the correct answer.

Step-by-step explanation:

 The sum of interior angles of a polygon is given by (n-2) x 180°, where n is the number of sides.

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  Option A is the correct answer.

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
Krista's mom has told her she needs to make the pen ½ the size that she had planned (5 feet long by 4 ½ feet wide). What will th
saw5 [17]

Answer:

1. area of new pen = 11 \frac{1}{4} ft^{2}

2. i. 5 feet by 2\frac{1}{4} feet

ii. 2 ½ feet by 4 ½ feet

Step-by-step explanation:

The size of the pen as planned = 5 ft long by 4 ½ ft wide

Area of the pen = length x width

                           = 5 x 4 ½

                           = 5 x \frac{9}{2}

Area of the pen = \frac{45}{2}

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But, Krista has to make the pen ½ the size of planned. So that;

area of new pen = ½ x 22 ½

        = ½ x \frac{45}{2}

        = \frac{45}{4}

        = 11 \frac{1}{4}

area of new pen = 11 \frac{1}{4} ft^{2}

The area of the new pen would be 11 \frac{1}{4} ft^{2}.

The possible values she could use are:

i. 5 feet by 2\frac{1}{4} feet

ii. 2 ½ feet by 4 ½ feet

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Answer:

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Step-by-step explanation:

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