8z-7=81
8z=88
z=11
Have a good day!
:0)
You have to add AB and for BC you have to add it then you get your answer
Answer:
A. Initially, there were 12 deer.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. After 15 years, there will be 410 deer.
D. The deer population incresed by 30 specimens.
Step-by-step explanation:

The amount of deer that were initally in the reserve corresponds to the value of N when t=0


A. Initially, there were 12 deer.
B. 
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. 
C. After 15 years, there will be 410 deer.
D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:
ΔN=N(15)-N(10)
ΔN=410 deer - 380 deer
ΔN= 30 deer.
D. The deer population incresed by 30 specimens.
<span>
Based on the rules of statistics</span>
68% of the data falls within 1 standard deviation of the mean
95% of the data falls within 2 standard deviation of the mean
99% of the data falls within 3 standard deviation of the mean
20 falls between the range of -56 to 56 (from the given 95%)
Hence we accept the null hypothesis; else, if the mean falls outside the
range, we reject the null hypothesis.
<span> </span>
There are 16 ounces in 1 pound: 5*16=80
80 ounces divided by 8 ounces gives you 10 8 ounce servings