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enot [183]
3 years ago
12

If G-H-I, and if GH=2x-9, HI=14, and GI=3x-8, then find GI.

Mathematics
1 answer:
CaHeK987 [17]3 years ago
6 0
The answer is -24 because a positive times a negative is a negative.
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Red line slope=3/4
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Aflati 2 numere stiind ca sunt direct proporționale cu 5 și 3 și suma lor este 100
aleksandrvk [35]

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idk

Step-by-step explanation:

5 0
3 years ago
An elevator was stopped at the 18th floor. Penny got in and went 14 floors down and got off. What floor did she get off at?
Papessa [141]
If the elevator stopped at the 18th floor and she got in and went 14 floors down and got off, she got off on the 4th floor
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3 years ago
A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far
ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3} (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2}) (1b)

Where:

x, y - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

r_{1}, r_{2} - Length of each vector, in kilometers.

\theta_{1}, \theta_{2} - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that r_{1} = 42\,km, r_{2} = 28\,km, \theta_{1} = 32^{\circ} and \theta_{2} = 154^{\circ}, then the resulting coordinates of the final position of the surveyor is:

(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})

(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]

(x,y) = (10.452, 34.531)\,[km]

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}

\theta \approx 16.840^{\circ}

And the distance from the camp is calculated by the Pythagorean Theorem:

r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}

r = 36.078\,km

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0
3 years ago
H=L^2/f•c solve for L
nata0808 [166]

Answer:

±sqrt( H *f•c)= L

Step-by-step explanation:

H=L^2/f•c

Multiply each side by fc

H *fc=L^2/f•c  * fc

H *f•c=L^2

Take the square root of each side

±sqrt( H *f•c)= sqrt(L^2)

±sqrt( H *f•c)= L

4 0
3 years ago
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