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Tanzania [10]
3 years ago
5

Algebra help ASAP :))))

Mathematics
1 answer:
never [62]3 years ago
3 0
G(x) = (1/2x)²

Place points at:
(-2, 2)
(-1, 0.5)
(0, 0)
(1, 0.5)
(2, 2)

The parabola should look something like this.

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Step-by-step explanation:

1. rewrite the equation in standard form: 4\cdot \frac{3}{2}\left(y-\left(-\frac{41}{24}\right)\right)=\left(x-\left(-\frac{3}{2}\right)\right)^2

2. find (h,k), the vertex. the vertex is \left(h,\:k\right)=\left(-\frac{3}{2},\:-\frac{41}{24}\right)

3. find the 'focal length' of the parabola - the focal length is the distance between the vertex and the focus. from the vertex we can see that the focal length, p, = 3/2

4. Parabola is symmetric around the y-axis and so the asymptote is a line parallel to the x-axis, a  distance p from the \left(-\frac{3}{2},\:-\frac{41}{24}\right) y coordinate which is at  -\frac{41}{24}\right). Set up the equation:

y=-\frac{41}{24}-p

5. substitute and solve:

y=-\frac{41}{24}-\frac{3}{2}

y = -\frac{77}{24}

hope this helps, ask me questions if you still don't understand.

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