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3 years ago

Given that Line segment B C is parallel to line segment E F which theorem or postulate proves ΔBCD =ΔFED

Mathematics

1 answer:

raketka [301]3 years ago

7 0

Seems like a trick question to me. Unless it states that D bisects CE and BF, then you can't say for sure.

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4 sisters love barrettes. they have a value pack that contains 92 barrettes. how many barrettes can each sister have if they sha

oee [108]

Answer:

Step-by-step explanation:

92÷4=23

There are a total of 92 barrettes and 4 sisters so you divide the total amount of barrettes with the total amount of people present.

6 0

4 years ago

Read 2 more answers

Please show steps in solving: B/3 + B/4 + B/6 =

alexandr1967 [171]

Answer:

= 3b/4

Step-by-step explanation:

= b . 4/12 + b . 3/12 + b . 2/12

Apply the fraction rule: a/c + b/c = a + b/c

= b . 4 + b . 3 + b . 2/12

= 4b + 3b + 2b/12

Add similar elements: 4b + 3b + 2b = 9b

= 9b/12

Cancel 9b/12: 3b/4

= 3b/4

5 0

3 years ago

Substitute a = 4, b = 1 and c = 5 into the expressions:<br> a + b - c

Soloha48 [4]

Answer:

a+b-c

4+1-5

5-5=0

THE ANSWER IS 0

3 0

3 years ago

What is the correct answer in the photo A. B. C. or .D please explain why

balu736 [363]

Answer:

I think its D)

Step-by-step explanation:

7x−3y+2=0

Add -7x to both sides.

7x−3y+2+−7x=0+−7x

−3y+2=−7x

Add -2 to both sides.

−3y+2+−2=−7x+−2

−3y=−7x−2

Divide both sides by -3.

−3y /−3 = −7x−2 /−3

which equals d)

I also use this app to convert equations to slope-intercept and it showed me this

8 0

3 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

3 years ago