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babymother [125]
4 years ago
15

the length of a rectangular classroom is 3 times its width. if the area covered by the classroom is 432 square feet, find the le

ngth and width of the classroom
Mathematics
1 answer:
emmainna [20.7K]4 years ago
4 0

Good morning

______

Answer:

w=12 feet

L =3×12=36 feet

Step-by-step explanation:

w×L=432 ⇔ w(3w) = 432 ⇔ 3w² = 432 ⇔ w² = 432÷3 = 144

Then  w = √(144) = 12.

____________________

:)

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What number is a common multiple of 5 and 9?
Yakvenalex [24]
45 is the answer. It is the least common multiple of 5 and 9. Multiples of 5: 5, 10,15,20,25, 30, 35, 40, 45 and multiples of 9: 9, 18, 27, 36, 45
6 0
3 years ago
Again ... Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S.
VladimirAG [237]

Answer:

We conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

We are given that a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time.

In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

Let \mu = <u><em>mean commute time in the U.S..</em></u>

So, Null Hypothesis, H_0 : \mu \geq 30 minutes      {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis, H_A : \mu < 30 minutes     {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                           T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean commute time = 27.6 minutes

            s = sample standard deviation = 19.6 minutes

            n = sample of people from the 2000 U.S. Census = 500

So, <u><em>the test statistics</em></u>  =  \frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }  ~ t_4_9_9

                                       =  -2.738

The value of t test statistic is -2.738.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis.</u>

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

4 0
4 years ago
Logarithms:
bogdanovich [222]

Answer:

  • 2^45 or ≈ 3.5*10^13

Step-by-step explanation:

<u>Given equation</u>

  • f(t) = 2^(kt)
  • f - number of cells, t - number of months, k- coefficient

<u>We got 32 cells in the first month. It means:</u>

  • t = 1, f(1) = 32

<u>Using these numbers we can find the coefficient k:</u>

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  • k = 5

<u>Then the equation becomes:</u>

  • f(t) = 2^(5t)

<u>Average time is 9 months, we can calculate the number of cells:</u>

  • f(9) = 2^(5*9) = 2^45 ≈ 3.5*10^13
5 0
3 years ago
Is y = x3 proportional or non proportional
weeeeeb [17]
No because for it to be anywhere near proportional it would have to be 3x
6 0
4 years ago
Read 2 more answers
What is the slope of the line?​
saveliy_v [14]

Answer:

2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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