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3 years ago

The area of the shaded triangle is 5x2+3x-4. What is the area of the entire figure?

Mathematics

1 answer:

Phoenix [80]3 years ago

3 0

The answer will be 2 cuz you multiply them at the answers

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5 - 3tan3x = 0 trên -π< x < π.

Lelu [443]

Step-by-step explanation:

the answer is In photo above

3 0

3 years ago

If the current temperature is 23∘ C, what is the temperature in degrees Fahrenheit?

den301095 [7]

Answer:

73.4

Step-by-step explanation: Multiply you celsius by 9. Then take that number then by 9. then add by 32

4 0

3 years ago

5. The half-life of Po-210 is 140 days. If the initial mass of the sample is 5

Anit [1.1K]

Answer:

1.25kg

Step-by-step explanation:

useing the problem the half life equation will be:

f(x)=5(0.5)^(x/140)

x is amount of days

so plugging in 280 for x will get 1.25kg

6 0

2 years ago

Consider this quadratic equation:

zhenek [66]

Answer:

a=2

b=0

c=12

Step-by-step explanation:

The standard form of a quadratic equation is ax²+bx+c=0

Here's the given equation:

2x²+12=0

You might notice that the term bx is not there (there is just ax² and c). That means that b is 0.

The term 2x² is the term ax² in this equation. The coefficient in the term is 2, so that means that a is 2

12 has no variable, so that means it'll be c in the equation.

Hope this helps!

6 0

3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$