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mixer [17]
3 years ago
14

Explain your answer ! ( WILL GIVE BRAINLST)

Mathematics
1 answer:
Nonamiya [84]3 years ago
7 0
B because
Solve for the first variable in one of the equations, then substitute the result into the other equation.
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How to solve (-7)+10?
slavikrds [6]
-7 + 10 = 3
=
10 + (-7)
Is the same as
10 - 8
…
Not sure if this was that helpful.. I hope it did.
8 0
3 years ago
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2.6 in.<br> 3 in. +<br> 6 in.
ivanzaharov [21]

Answer:

11.6in

Step-by-step explanation:

5 0
3 years ago
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The perimeter of an equilateral triangle is 15 inches more than the perimeter of a​ square, and the side of the triangle is 8 in
Setler [38]

<u>ANSWER:  </u>

The length of a side of the triangle is 17 inches.

<u>SOLUTION: </u>

Given, the perimeter of an equilateral triangle is 15 inches more than the perimeter of square.

And the side of the triangle is 8 inches longer than the side of the square.

Let the length of the side of a triangle be x.

And the length of the side of a square be y.

perimeter of triangle = a + b + c , where a , b, c represents side

perimeter of square = a + a + a +a , where a represents side

Given, the perimeter of an equilateral triangle is 15 inches more than the perimeter of square.  Hence we form a equation as

Then, x + x + x = 15 + y + y + y + y

3x = 15 + 4y ---- (1)

Now, given that, x = 8 + y ---- (2)

Substitute (2) in (1)

3(8 + y) = 15 + 4y

24 + 3y = 15 + 4y

4y – 3y = 24 – 15

y = 9

Now, substitute y value in (2)

x = 8 + 9  = 17

Hence, the length of a side of the triangle is 17 inches.

5 0
4 years ago
When I square my number, I get the same answer as when I multiply my number by 10 and then add 144. My number is positive. What
exis [7]

Answer:

your number is 18

Step-by-step explanation:

x^2 = (x × 10 ) + 144

x^2 = 10x + 144

x^2 - 10x - 144 = 0

using quadratic method

your answer should be

(x- 18) ( x+8 )

8 0
3 years ago
Fifteen pencils are sold for $750. what is the cost for 1 pencil ?​
aniked [119]
One pencils cost $50
Because you to do 750/15 to get you X
3 0
3 years ago
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