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Bess [88]
3 years ago
10

HELP!!! I got the first part done but I feel as though I did it wrong because I can't seem to get part 2 or 3 done.

Mathematics
2 answers:
Grace [21]3 years ago
6 0
Sent a picture of the solution to the problem (s).

Stolb23 [73]3 years ago
6 0

Answer:

It's all below...

Step-by-step explanation:

Part 1.

quadratic poynomial function:   f(x)=x2−5x+6

linear binomial:   x−2

x−3x−2x2−5x+6x2−2x−−−−−−−−−−3x+6−3x+6−−−−−−−−0

Part 2.  

f(2)=22−5(2)+6=4−10+6=−6+6=0

Part 3.  


The remainder theorem says that if f(x) is divided by x-a, then f(a) will be the remainder. When we divided f(x) by x - 2 , we got a remainder of 0, which by the remainder theorem implies f(2) = 0.  That means x-2 is a factor of f(x).

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Given f(x) = 2x - 2/4 the quantity of 2x minus 2 divided by 4, solve for f−1(3).
olga_2 [115]

The answer is that f-1(3) = 7.

In order to find the answer, we first must find the inverse function. The f-1 indicates that we are looking for an inverse. To find any inverse, we first must switch the x and f(x) values. We then solve for the new f(x), which gives us the inverse.

f(x) = (2x - 2)/4 ----> Switch x and f(x)

x = (2f(x) - 2)/4 -----> Multiply both sides by 4

4x = 2f(x) - 2 ----0-> Add 2 to both sides

4x + 2 = 2f(x) ------> Divide both sides by 2

f-1(x) = (4x + 2)/2

Now that we have the inverse function, we can put in 3 and find the answer.

f-1(x) = (4x + 2)/2

f-1(3) = (4(3) + 2)/2

f-1(3) = (12 + 2)/2

f-1(3) = (14)/2

f-1(3) = 7

4 0
4 years ago
A farmer has 212 acres of land for sale. He divides the land into 8 equal sections. About how many acres are in each section?
faust18 [17]
About 26 and a half acres of land in each section
4 0
3 years ago
Ten minus five point six
lianna [129]
4.4 is the answer cause 5.6 plus 4.4 is 10
8 0
3 years ago
Find all zeros of f(x)=x^4-3x^3+6x^2+2x-60 given that 1+3i is a zero of f(x) ​
Triss [41]

Answer:

The roots of f(x) are: -2, 3, (1+3i) and (1-3i)

Step-by-step explanation:

We are given an expression:

f(x)=x^4-3x^3+6x^2+2x-60

(1+3i) is a root of f(x)

We have to find the remaining roots of f(x).

Since, (1+3i) is a root of f(x),

x-(1+3i)

is a factor of given expression.

Now, we check if (1 - 3i) is a root of given function.

f(x)=x^4-3x^3+6x^2+2x-60\\f(1-3i)=(1-3i)^4-3(1-3i)^3+6(1-3i)^2+2(1-3i)-60\\= (28+96i)-3(-26+18i)+6(-8-6i)+2(1-3i)-60 = 0

Thus, (1-3i) is also a root of given function.

Since, (1-3i) is a root of f(x),

x-(1-3i)

is a factor of given expression.

Thus, we can write:

(x-(1+3i))(x-(1-3i))\text{ is a factor of f(x)}\\x^2-x(1-3i)+x(1+3i)+(1-3i)(1+3i)\text{ is a factor of f(x)}\\x^2-2x+10\text{ is a factor of f(x)}

Dividing f(x) by above expression:

\displaystyle\frac{x^4-3x^3+6x^2+2x-60}{x^2-2x+10} = x^2-x-6

To find the root, we equate it to zero:

x^2-x-6 = 0\\x^2 - 3x+2x-6=0\\x(x-3)+2(x-3)=0\\(x+2)(x-3) = 0\\x = -2, x = 3

Thus, the roots of f(x) are: -2, 3, (1+3i) and (1-3i)

4 0
4 years ago
What is the answer to the question
malfutka [58]

Answer:

10

Step-by-step explanation:

Double the first equation we get 10p + 6s = 101.00

Subtract the second equation from the one we just got,

=> (10p + 6s) - (2p + 6s) = 101.00 - 31.00

                                8p = 80

                                   p = 10

5 0
3 years ago
Read 2 more answers
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