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slavikrds [6]
3 years ago
11

Which system of equations can you use to find the roots of the equation 2x3 + 4x2 – x + 5 = –3x2 + 4x + 9?

Mathematics
2 answers:
Viefleur [7K]3 years ago
7 0

Answer:

C is the answer

Step-by-step explanation:

Degger [83]3 years ago
3 0

Answer:

y=2x^3+4x^2-x+5

y=-3x^2+4x+9

Step-by-step explanation:

The given equation is in the form 2x^3+4x^2-x+5=-3x^2+4x+9

We have to evaluate the correct system of equations which can be used to find the roots of the equation.

We can find the root of the equation by plotting the graph of the equations. In order to graph, we can assume the left and right hand side of the given equation as two separate equations.

Therefore, we have

y=2x^3+4x^2-x+5

y=-3x^2+4x+9

Now, we plot the graph of these two equations in the same coordinate plane. The intersection point (s) would be the roots of the given equation.

Hence, the system of equation that we can use to find the root of the given equation is

y=2x^3+4x^2-x+5

y=-3x^2+4x+9

Last option is correct.

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A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence
Varvara68 [4.7K]

Answer:

(a): The 95% confidence interval is (46.4, 53.6)

(b): The 95% confidence interval is (47.9, 52.1)

(c): Larger sample gives a smaller margin of error.

Step-by-step explanation:

Given

n = 30 -- sample size

\bar x = 50 -- sample mean

\sigma = 10 --- sample standard deviation

Solving (a): The confidence interval of the population mean

Calculate the standard error

\sigma_x = \frac{\sigma}{\sqrt n}

\sigma_x = \frac{10}{\sqrt {30}}

\sigma_x = \frac{10}{5.478}

\sigma_x = 1.825

The 95% confidence interval for the z value is:

z = 1.960

Calculate margin of error (E)

E = z * \sigma_x

E = 1.960 * 1.825

E = 3.577

The confidence bound is:

Lower = \bar x - E

Lower = 50 - 3.577

Lower = 46.423

Lower = 46.4 --- approximated

Upper = \bar x + E

Upper = 50 + 3.577

Upper = 53.577

Upper = 53.6 --- approximated

<em>So, the 95% confidence interval is (46.4, 53.6)</em>

Solving (b): The confidence interval of the population mean if mean = 90

First, calculate the standard error of the mean

\sigma_x = \frac{\sigma}{\sqrt n}

\sigma_x = \frac{10}{\sqrt {90}}

\sigma_x = \frac{10}{9.49}

\sigma_x = 1.054

The 95% confidence interval for the z value is:

z = 1.960

Calculate margin of error (E)

E = z * \sigma_x

E = 1.960 * 1.054

E = 2.06584

The confidence bound is:

Lower = \bar x - E

Lower = 50 - 2.06584

Lower = 47.93416

Lower = 47.9 --- approximated

Upper = \bar x + E

Upper = 50 + 2.06584

Upper = 52.06584

Upper = 52.1 --- approximated

<em>So, the 95% confidence interval is (47.9, 52.1)</em>

Solving (c): Effect of larger sample size on margin of error

In (a), we have:

n = 30     E = 3.577

In (b), we have:

n = 90    E = 2.06584

<em>Notice that the margin of error decreases when the sample size increases.</em>

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