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mezya [45]
2 years ago
9

Use the Distance Formula to find the distance to the nearest tenth between A(-7, -4) and B(-2, 0).

Mathematics
1 answer:
goldenfox [79]2 years ago
8 0
A(-7,-4) B(-2,0)
√[(x'-x)^2+(y'-y)^2]
√(-2-(-7)^2+(0-(-4)^2
√(5^2)+(4^2)
√25+16
√41 

the distance is approximately 6.4 units
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Area as a sum:<br> Area as a Product:<br><br><br> I need the are as a sum Nd a product
PSYCHO15rus [73]

Given:

The area model.

To find:

The area as a sum and area as a product.

Solution:

The four terms of the area model are 2x^2,10x, 3x, 15.

The area as a sum is the sum of all the terms of given area model.

Area as a sum = 2x^2+10x+3x+15

                        = 2x^2+13x+15

The area as a product is the factor form of sum of all the terms of given area model.

Area as a product = 2x^2+10x+3x+15

                        = 2x(x+5)+3(x+5)

                        = (x+5)(2x+3)

Therefore, the area as a sum is 2x^2+13x+15 and the area as a product is (x+5)(2x+3).

8 0
3 years ago
find the equation of the straight line passing through the point (0,-1) which is perpendicular to the line y=-3/4x-3
barxatty [35]

Answer:

y = \frac{4}{3} x - 1

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - \frac{3}{4} x - 3 is in this form

with slope m = - \frac{3}{4}

the slope of a perpendicular line is the negative reciprocal of m, hence

m_{perpendicular} = \frac{4}{3}

(0 , - 1 ) is the y-intercept ⇒ c = - 1

y = \frac{4}{3} x - 1  ← equation of perpendicular line


4 0
3 years ago
2/3 x+(-3)+(-2)-1/3 x
erik [133]

Answer: what method are you using?

Step-by-step explanation:

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3 years ago
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4 0
2 years ago
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if a, b, and c are sides of a right triangle, which of the following sides are also sides of a right triangle
suter [353]

Answer:

A

Step-by-step explanation:

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5 0
3 years ago
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