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nataly862011 [7]
3 years ago
11

The specific heat capacity of oxygen is 918 J/kg °C. The specific heat capacity of water is 4181 J/kg °C. Which substance will r

equire more energy to raise its temperature by 1°C?
Chemistry
1 answer:
Vsevolod [243]3 years ago
7 0

Answer:

Water

Explanation:

Given the specific heat of oxygen is 918J/kg°C and the specific heat of water is 4181 J/kg°C.

Consider 1Kg mass of each substance.

Now 1 Kg of oxygen needs 918 J of energy to raise its temperature by 1°C

Also 1 Kg of water needs 4181 J of energy to raise its temperature by 1°C.

Clearly water recquires more energy when compared to oxygen.

Basically specific heat capacity is the amount of energy recquired to raise the temperature of a 1 kg body by 1°C.

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Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation 2 H 2 O 2 ( aq ) ⟶ 2
Ede4ka [16]

Answer:

The value of temperature for unanalysed reaction is 456.1 K

Explanation:

Step 1: Data given

The activation energy of uncatalyzed reaction is 75.0 kJ/mol.

The activation energy of catalyzed reaction is 49.0 kJ/mol.

The temperature for catalyzed reaction is  25 °C

<u>Step 2:</u>  The balanced equation

2 H2O2(aq) ⟶ 2H2O(l) + O2(g)

<u>Step 3:</u> According to Arrhenius equation:

k = Ae ^ (-Ea/RT)

⇒ with k = the rate constant

⇒ with Ea = the activation energy = 49 kJ/mol

⇒ with R = the universal gas constant = 8.314 J/mol*K

⇒ with T = the temperature  = 298 K

For uncatalyzed reaction, the rate constant is calculated as:

k(uncatalyzed) = Ae ^ (-75000/8.314 J/mol*K * T)

k(uncatalyzed) = Ae ^ (-9020.93/T)

For catalyzed reaction, the rate constant is calculated as:

k(catalyzed) = Ae ^ (-Ea(catalyzed)/RT))

 ⇒ with Ea(catalyzed) = 49000 J/mol

 ⇒ with T = 298 K

k(catalyzed) = Ae ^ (-49000J/(8.314J/mol *K * 298K))

k(catalyzed) = Ae ^(-19.78)

k(catalyzed) = k(uncatalyzed)

Ae^(-19.78) = = Ae ^ (-9020.93/T)

-19.78 = -9020.93/T

T = -9020.93/-19.78

T = 456.1 K

The value of temperature for unanalysed reaction is 456.1 K

8 0
3 years ago
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Answer:

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Answer:

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Explanation:

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3 years ago
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FrozenT [24]

Answer:

0.100 M AlCl₃

Explanation:

The variation of boiling point by the addition of a nonvolatile solute is called ebullioscopy, and the temperature variation is calculated by:

ΔT = W.i

Where W = nsolute/msolvent, and i is the Van't Hoff factor. Because all the substances have the same molarity, n is equal for all of them.

i = final particles/initial particles

C₆H₁₂O₆ don't dissociate, so final particles = initial particles => i = 1;

AlCl₃ dissociates at Al⁺³ and 3Cl⁻, so has 4 final particles and 1 initial particle, i = 4/1 = 4;

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MgCl₂ dissociates at Mg⁺² and 2Cl⁻, so has 3 final particles and 1 initial particle, i = 3/1 = 3.

So, the solution with AlCl₃ will have the highest ΔT, and because of that the highest boiling point.

8 0
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worty [1.4K]

Answer:

Iron, sugar, glass, neon

Explanation:

Anything that you can touch is matter

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