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Otrada [13]
3 years ago
14

Which phrase describes the pattern? 1, 7, 19, 43...Question 2 options: add 6 ,multiply by 3 and then add 1 multiply ,by 3 and th

en add 4 ,multiply by 2 and then add 5
Mathematics
1 answer:
torisob [31]3 years ago
4 0
Answer 
<span>multiply by 2 and then add 5

1 x 2 + 5 = 2+5 =7
7 x 2 + 5 = 14 +5 = 19
19 x 2 +5 = 38 +5 = 43</span>
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Find the value of X and give a reason for the relation ship between the angles.
Ostrovityanka [42]

Answer:

x = 55

Step-by-step explanation:

(x - 14) + 99 + 220 = 360

x - 14 + 99 + 220 = 360

x - 14 + 319 = 360

x + 305 = 360

x = 360 - 305

x = 55

-TheUnknownScientist

8 0
3 years ago
Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx
shutvik [7]

\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)

Let v=x+y, so that \dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}:

\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1

Now the ODE is separable, and we have

\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx

Integrating both sides gives

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx

For the integral on the left, rewrite the integrand as

\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v

Then

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C

and so

\csc v-\cot v=x+C

\csc(x+y)-\cot(x+y)=x+C

Given that y(0)=\dfrac\pi2, we find

\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1

so that the particular solution to this IVP is

\csc(x+y)-\cot(x+y)=x+1

5 0
3 years ago
Does the table represent a linear or nonlinear function? How do you know?<br> (PLS HELP ASAP)!
Fittoniya [83]

Answer:

linear

Step-by-step explanation:

5 0
3 years ago
Please let me know ASAP
aksik [14]

Answer:

∠ BAC = 80°

Step-by-step explanation:

The sum of the interior angles of quadrilateral ACDB = 360°

DB and DC are tangents to the circle, thus

∠ DBA = ∠ ACD = 90° ( angle between tangent/ circle at point of contact )

Thus

∠ BAC + 90° + 90° + 100° = 360°

∠ BAC + 280° = 360° ( subtract 280° from both sides )

∠ BAC = 80°

4 0
3 years ago
Read 2 more answers
Solve A=LW for width
Nataly_w [17]
Area= (length)(width)

divide by (length) on both sides.

(width)= (area)/(length).

Your best bet is treating area, length, and width as numbers. You can plug in numbers and take them out in the end. Hope this helps!
5 0
3 years ago
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