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Novay_Z [31]
3 years ago
11

What is the remainder when x^2+4 is divided by x-2?

Mathematics
1 answer:
tangare [24]3 years ago
3 0

The remainder is 8

Step-by-step explanation:

Given expression is

x^2+4

Which has to be divided by:

x-2

We have used the long division method for the given problem

The process is completed in two steps (Picture Attached)

Hence,

The remainder is 8

Keywords: Division, long division

Learn more about long division at:

  • brainly.com/question/6465937
  • brainly.com/question/6431715

#LearnwithBrainly

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Kenny has a jar full of nickels and dimes. If he counted the money in his jar, how much does he have ?
shusha [124]

Answer:

Step-by-step explanation:

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4 0
2 years ago
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??? times 4/9 is negative 8
Nitella [24]
-2/9 x 4/9 is -8
so the answer is -2/9
5 0
3 years ago
Read 2 more answers
The radius of a circular disk is given as 24 cm with a maximum error in measurement of 0.2 cm. (a) Use differentials to estimate
hoa [83]

Answer:

9.60πcm²

Step-by-step explanation:

Area of circular disk, A = πr²

Differntiate A with respect to r

dA/dr = π * (2r^(2-1)) /(2-1) + C

dA/dr = π * 2r/1

dA/dr = 2πr

dA = 2πr * dr

dA = 2πrdr

dA = maximum error ; dr= Error in measurement = 0.2 cm ; r = radius = 24cm

dA = 2π * 24 * 0.2

dA = 9.60πcm²

3 0
2 years ago
K(x) k(-3) 2x^2-5x+3
valentina_108 [34]

Answer:

When k(x) is 2x² - 5x + 3, k(-3) = 36.

Step-by-step explanation:

k(x) = 2x² - 5x + 3

Substitute the input of x.

k(-3) = 2(-3)² - 5(-3) + 3

Square -3.

k(-3) = 2(9) - 5(-3) + 3

Multiply 2 and 9.

k(-3) = 18 - 5(-3) + 3

Multiply -5 and -3.

k(-3) = 18 + 15 + 3

Add 18 and 15.

k(-3) = 33 + 3

Add 33 and 3.

k(-3) = 36.

6 0
2 years ago
Emil bought a camera for $268.26, including tax. He made a down payment of $12.00 and paid the balance in 6 equal monthly paymen
AVprozaik [17]
Firstly, subtract the cost that Emil has already put down;
268.26-12= 256.26
Then divide by the monthly installments
256.26/ 6= 42.71
Therefore, Emil pays $42.71 per month 
Hope this helps :) <span />
8 0
3 years ago
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