IMPORTANT:
If you're trying to factor a quadratic in Algebra I:There are no two integers that can solve this problem!
Your quadratic is <em>prime</em>!
If you're trying to solve a quadratic (find x):The factoring approach will not work for the same reasons listed above.
Try using splitting the middle or the quadratic formula instead.
Here's how you would solve it from a more advanced approach.
If you don't know what this stuff is, just ignore it.
ab = -18, a + b = -9
Find a in terms of b.
a = -9-b
Substitute this for a in the first equation.
(-9-b)b = -18
-9b-b² = -18
Multiply everything by -1 to get rid of all these negative signs.
b² + 9b = 18
Bring over that 18.
b² + 9b - 18 = 0
Apply the quadratic formula.
(a = 1, b = 9, c = -18)
If you need to write two distinct numbers, just write out one with a + and one with a - in place of the plus-minus sign.
Not sure but i would go bottom left corner answer
1. <span>Simplify -9 + -2m to -9 - 2m
-3m = -9 - 2m
2. </span><span>Add </span>2m <span>to both sides
-3m + 2m = -9
3. </span><span>Simplify -3m + 2m to -m
-m = -9
4. </span><span>Multiply both sides by </span><span><span>−<span>1
m = 9
Done! :) our answer is m = 9</span></span></span>
Mrs.Lombardo.<span>if you do the math out, 4/5 and 2/3 give you an LCD (Least Common Denominator) of 15, so this means 4/5 = 12/15, and 2/3 = 10/15. 4/5 is greater than 2/3. </span>
Answer:
Does the answer help you?