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3 years ago

Ava collects 9 insects in her net issac collects 8 more then Ava how many insects does Isaac collect

Mathematics

2 answers:

butalik [34]3 years ago

7 0

Answer:

Step-by-step explanation:

available has 9, issac gets 8. 9 plus 8 equals 17

gregori [183]3 years ago

4 0

Answer:

Seventeen insects

Step-by-step explanation:

9+8=17

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NEED HELP WITH THESE QUESTIONS

amm1812

For this case we must solve the following questions:

Question 1:

We should simplify the following expression:

$\frac {\frac {m ^ 2 * n ^ 3} {p ^ 3}} {\frac {mp} {n ^ 2}} =$

Applying double C we have:

$\frac {m ^ 2 * n ^ 3 * n ^ 2} {mp * p ^ 3} =$

By definition of multiplication of powers of the same base we have to place the same base and add the exponents: $\frac {m ^ 2 * n ^ 5} {m * p ^ 4} =$

Canceling common terms:

$\frac {mn ^ 5} {p ^ 4}$

Answer:

Option A

Question 2:

We should simplify the following expression:

$\frac {3xyz ^ 2} {6y ^ 4} * \frac {2y} {xz ^ 4}$

So, we have:

$\frac {3xyz ^ 2 * 2y} {6y ^ 4 * xz ^ 4} =\\\frac {6xy ^ 2z ^ 2} {6y ^ 4xz ^ 4} =$

Simplifying common terms:

$\frac {1} {y ^ 2z ^ 2}$

Answer:

Option D

Question 3:

We factor the following expressions to rewrite the experience:

$r ^ 2 + 7r + 10$ : We look for two numbers that multiplied give 10 and added 7:

$(r + 5) (r + 2)$

$r ^ 2-5r-50:$ We look for two numbers that multiplied give -50 and added -5:

$(r-10) (r + 5)$

$3r-30 = 3 (r-10)$

Rewriting the given expression we have:

$\frac {(r + 5) (r + 2) * 3 (r-10)} {3 (r-10) (r + 5)} =$

We simplify common terms in the numerator and denominator we have:

$(r + 2)$

Answer:

Option D

4 0

3 years ago

Read 2 more answers

2852.1 rounded to the nearest tenth of a mile

katrin2010 [14]

2852.1 rounded to the nearest tenth of a mile is still 2852.1

5 0

3 years ago

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I have 8 pennies and some quarters, nickels, and dimes. The number of pennies plus nickels equals the number of dimes. I have 3

Darina [25.2K]

There are five nickels.

Let w = the number of pennies; x = the number of nickels; y = the number of dimes; z = the number of quarters.

Then, we have three equations with four unknowns:

(1) w + x = y

(2) 3w = 2z

(3) 2y = 3z

However, there is a fourth unstated condition: w, x, y, and z must all be integers.

Assume that z = 6 (to avoid fractions).

From Equation (2), w = 4.

From Equation (3), y = 9.

Insert the values for w and y into equation (1).

4 + x = 9

x = 9 – 4 = 5

Thus, there are 4 pennies, 5 nickels, 9 dimes, and 6 quarters.

Check: 4 pennies + 5 nickels = 9 dimes

6 quarters + 4 pennies = 3 quarters for every 2 pennies

9 dimes + 6 quarters = 3 dimes for every 2 quarters

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3 years ago

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Seth is trying to find the unit price for a package of blank compact discs on sale at 10 for $5.49. Find his mistake and correct

hoa [83]

It is about .55 cents for each disk

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3 years ago

Sec^2 (pi/2 - x) * [sin^2 (x) - sin^4 (x)]

Bad White [126]

Answer:

Explanation:

Identity: sec2θ=1+tan2θ

sec2(π2−x)−1=1+tan2(π2−x)−1

=tan2(π2−x)

Identity: tan(π2−θ)=cotθ

=cot2x

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3 years ago