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marissa [1.9K]
3 years ago
13

Need help ASAP please please

Mathematics
2 answers:
natali 33 [55]3 years ago
5 0
Open end arrow pointing to the right from -9 to past -2

For all x >-9 is any number on the number line above, to the right of -9
Rama09 [41]3 years ago
4 0

Answer:

-10,-11, -12

Step-by-step explanation:

All are bigger

You might be interested in
Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu
Luda [366]

Answer:

  11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

  P(z ≤ -6) ≈ 9.86588×10^-10

and

  P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

  0.50^t = 0.000290372

  t·log(0.50) = log(0.00290372) . . . . take logarithms

  t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

  t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

  t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0
3 years ago
I need the answers to this
adoni [48]
It would be -140=x... to get this you would multiply x over 14 by 14... since you did it to one side then you have to do it to the other
6 0
3 years ago
Read 2 more answers
Please help I will mark brainlist if correct
MakcuM [25]

The admission fee at a fair is $2.00 for children and $4.00 for adults.

On Saturday 2,500 people entered the fair and $7,000.00 were collected.

How many children and how many adults attended? Give your answer, using x for children, y for adults.

Form of: x =, and y =

 

Let K = no. of children

Let A = no. of adults

 

2500 people mean

Kids + Adults

 

K + A = 2500

K = 2500 – A

 

2K + 4A = 7000

K + 2A = 3500

 

(2500 – A) + 2A = 3500

A = 3500 – 2500

(A = 1000, adults)

 

K = 2500 – A

K = 2500 -1000

(K = 1500, Kids)

 

CHECK:

1500*2 = $3000

1000*4 = $4000

<span>(Total = $7000, people.). </span>

<span>
</span>

<span>Hope this helps:</span>

6 0
3 years ago
Candice is preparing for her final exam in Statistics. She knows she needs an 74 out of 100 to earn an A overall in the course.
Salsk061 [2.6K]

Answer:

Hence the correct option is option b) Yes, the upper level of one standard deviation is 72.

A score of 74 is not within one standard deviation of the mean.

Step-by-step explanation:

Here the given details are,

Mean = 68  

SD = 4  

Distribution is normal.  

Z-score for x = 74 is given as below:  

Z = (X - mean)/SD\\Z = (74 - 68)/4\\Z = 1.5  

So, the score of 74 is 1.5 standard deviations from the mean.  

Mean + 1\timesSD = 68 + 1\times4 = 72Mean - 1\timesSD = 68 - 1\times4 = 64  

Therefore the score is not lies between 64 and 72.  

Yes, the upper level of one standard deviation is 72.  

3 0
3 years ago
Which algebraic expression is equivalent to this expression?
Eduardwww [97]

Answer:

a

Step-by-step explanation:

9(5x)=45x

9(2)=18

4(8)=32

4(-x)=-4x

45x-4x=41x

32+18=50

41x+50

6 0
3 years ago
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