Given:
The function is

To find:
The inverse of the given function.
Solution:
We have,

Substitute m(x)=y.

Interchange x and y.

Add square of half of coefficient of y , i.e.,
on both sides,


![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)
Taking square root on both sides.

Add
on both sides.

Substitute
.

We know that, negative term inside the root is not real number. So,


Therefore, the restricted domain is
and the inverse function is
.
Hence, option D is correct.
Note: In all the options square of
is missing in restricted domain.
The answer is D. They both had the same proportion.
Hope this helps!!!
Find the prices per ounce by dividing the dollars by the number of ounces:-
1.79 / 15 = 0.1193 dollars per ounce
1.49 / 12 = 0.1242 dollars per ounce
So the first one is the better buy.
The formula is

We have:


Substituting these values into the formula, we have


⇒ divide each term by 16

⇒ find the pair of numbers that multiply to give 4 and sum gives -5 which is -1 and -4

⇒ We have two values of t

⇒


⇒

The time when the projectile reached 64 feet is at t=1 and t=4