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3 years ago

The quadratic equation 2x^2 + bx + 18 = 0 has a double root. Find all possible values of b.

1 answer:

4 0

When a quadratic equation ax^2+bx+c has a double root, the discriminant,
D=b^2-4ac=0
Here
a=2,
b=b,
c=18
and
D=b^2-4ac=b^2-4*2*18=0
solve for b
b^2-144=0
=> b= &pm; sqrt(144)= &pm; 12

So in order that the given equation has double roots, the possible values of b are &pm; 12.

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Mr. Bryon bought a gas can with 4 1/4 gallons of gasoline in it. He used 1/4 of the amount in the can to mow his lawn. How many

alisha [4.7K]

Do 4 1/4 - 1/4 which is easy, just take away the 1/4 and you get 4, so he used 1/4 gallons

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3 years ago

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The table shows the masses of four objects. A 2-column table with 4 rows. The first column labeled object has entries book, rock

Ede4ka [16]

Answer:

ROCK 2.3 kg

is about 22.5N

Step-by-step explanation:

To convert kg>>>>N

You multiply by 9.8 (this is good for estimating, but use more decimal places like, 9.80665 for more exact calculations).

You can divide N÷9.8 to find kg

see image

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2 years ago

state domain and range, intercepts, relative max and relative mins points and values, intervals of increase and decrease, interv

Anarel [89]

The domain of the graph is -∝ < x < ∝ and the range of the graph is -∝ < y < ∝. Also, the graph has no axis of symmetry

<h3>The domain and range of the graph</h3>

From the graph, we can see that the x values extend indefinitely

So, the domain of the graph is -∝ < x < ∝

From the graph, we can see that the y values extend indefinitely

So, the range of the graph is -∝ < y < ∝

<h3>The intercepts</h3>

This is where the graph crosses the axes

So, we have the intercepts to be

x-intercept = -4, -2 and 2
y-intercept = -9

<h3>Relative max and relative mins points and values, </h3>

The graph has a relative maximum at (3, 3) and the relative minimum are (0.5, 10)

<h3>Intervals of increase and decrease, </h3>

There are the intervals where the function increases and decreases

So, we have the intervals to be

Increasing interval: (0.5, ∝) and (-∝, -3)
Decreasing interval: (-3, 0.5)

<h3>Intervals of positive and negative,</h3>

There are the intervals where the function is positive and negative

So, we have the intervals to be

Positive interval: (-4, -2) and (2, ∝)
Negative interval: (-∝, -4) and (-2, 2)

<h3>The symmetry</h3>

This is the line that divides the graph equal part

In this case, the graph has no axis of symmetry

<h3>The end behavior</h3>

Using the intervals where the function is positive and negative, the end behavior is

As x ⇒ ∝, f(x) ⇒ +∝
As x ⇒ -∝, f(x) ⇒ -∝

Read more about functions at:

brainly.com/question/3951754

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1 year ago

IM GIVING BRAINLIEST!!!PLEASE HELP !! I know ITS not B or D so it’s either a or c!!

Novay_Z [31]

Answer:

i think its c

Step-by-step explanation:

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2 years ago

Read 2 more answers

A data includes 108 body temperature od healthy adult humans having a mean of 98.2 f and a standard deviation of .64f. Contruct

leonid [27]

Answer: ( 98.04f, 98.40f ), it is not accepted

Step-by-step explanation: the question is suggesting we construct a 99% confidence interval for mean body temperature.

The formulae for Constructing a 99% confidence interval is given below as

u = x + Zα/2 × (s/√n)........... For the upper limit

u = x - Zα/2 × (s/√n)........... For the lower limit

Where u = population mean

x = sample mean = 98.2

s = sample standard deviation = 0.64

n = sample size = 108.

Zα/2 = critical value for a 2 tailed test performed at a 1% level of significance ( 100% - 99%) = 2.58

We are making use of our z test because sample size is greater than 30 ( n = 108).

By substituting the parameters, we have that

For upper limit

u = x + Zα/2 × (s/√n)

u = 98.2 + 2.58 ( 0.64/√108)

u = 98.2 + 2.58 ( 0.0616)

u = 98.2 + 0.1589

u = 98.4

For lower limit

u = x - Zα/2 × (s/√n)

u = 98.2 - 2.58 ( 0.64/√108)

u = 98.2 - 2.58 ( 0.0616)

u = 98.2 - 0.1589

u = 98.04.

Hence the 99% confidence interval for mean temperature of human is ( 98.04f, 98.40f )

Using 98.6f as the average mean body temperature is wrong because it is out of the confidence interval calculated above.

Our confidence interval states that at 99% confidence interval, an average human temperature should be at least 98.04f and at most 98.40f.

98.6f is out of the range.

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3 years ago