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Ostrovityanka [42]
3 years ago
9

The probability that an egg on a production line is cracked is 0.01. Two eggs are selected at random from the production line. F

ind the probability that at least one egg is cracked. Write the entire decimal answer.
Mathematics
1 answer:
musickatia [10]3 years ago
5 0

Answer:

P(X \geq 1)=1-P(X

P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801

And replacing we got:

P(X \geq 1) = 1-0.9801 = 0.0199

Step-by-step explanation:

Let X the random variable of interest "number of craked eggs", on this case we now that:

X \sim Binom(n=2, p=0.01)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(x \geq 1)=1-P(X

And we can find the probability:

P(X=0)=(2C0)(0.01)^0 (1-0.01)^{2-0}=0.9801

And replacing we got:

P(X \geq 1) = 1-0.9801 = 0.0199

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All it is asking is to plug the given x values into the equation (which are 0, 2, 4) and see what you get for y.
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