Answer:
the ratio of the distance in inches travelled by the tip of the hour hand to the distance in inches travelled by the tip of the minute hand is <em>0.125</em>.
Step-by-step explanation:
The given information is:
- length of the hour hand, l = 6 inches
- length of the minute hand, b = 8 inches
Therefore, since the tip of the minute moves from 12 to 3, it moved a distance of:
s₁ = r θ
s₁ = (8)(π/2)
s₁ = 4π inches
The hour hand moves 30 degrees / 60 = 1/2 degree in a minute.
Therefore, in 30 minutes the hour hand moves a distance of:
s₂ = r θ
s₂ = 6(30×1/2×π/180)
s₂ = π/2 inches
Therefore, the ratio of the distance in inches travelled by the tip of the hour hand to the distance in inches travelled by the tip of the minute hand is:
s₂ / s₁ = (π/2) / 4π
<em>s₂ / s₁ = 0.125</em>
