Answer:
-16
Step-by-step explanation:
im just taking a guess.
x+4>-12
-4 -4
---------------
4's cancel out and -12+-4=-16
Again this is just a guess.
Adjacent angles<span> are two </span>angles<span> that have a common vertex and a common side.
hope this helps</span>
I believe the answer would be c=12. i hope that’s what the question is asking for lol.
Answer:
![P = \frac{2}{3} [J(y)] - 2](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B2%7D%7B3%7D%20%5BJ%28y%29%5D%20-%202)
Step-by-step explanation:
If Jojo completes P number of paintings working w weeks then the relation between P and w is given by 
. ........ (1)
Again, the function J(y) represents how many weeks per year she spends painting.
So, w = J(y). ...... (2)
Therefore, the composite function which represent how many paintings Jojo completes in a year, is given by
(Answer)
Answer:
f(x)=-18x^2
Step-by-step explanation:
Given:
1+Integral(f(t)/t^6, t=a..x)=6x^-3
Let's get rid of integral by differentiating both sides.
Using fundamental of calculus and power rule(integration):
0+f(x)/x^6=-18x^-4
Additive Identity property applied:
f(x)/x^6=-18x^-4
Multiply both sides by x^6:
f(x)=-18x^-4×x^6
Power rule (exponents) applied"
f(x)=-18x^2
Check:
1+Integral(-18t^2/t^6, t=a..x)=6x^-3
1+Integral(-18t^-4, t=a..x)=6x^-3
1+(-18t^-3/-3, t=a..x)=6x^-3
1+(6t^-3, t=a..x)=6x^-3
That looks great since those powers are the same on both side after integration.
Plug in limits:
1+(6x^-3-6a^-3)=6x^-3
We need 1-6a^-3=0 so that the equation holds true for all x.
Subtract 1 on both sides:
-6a^-3=-1
Divide both sides by-6:
a^-3=1/6
Raise both sides to -1/3 power:
a=(1/6)^(-1/3)
Negative exponent just refers to reciprocal of our base:
a=6^(1/3)
