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expeople1 [14]
3 years ago
14

The owner of a small business buys coats for $60 each. He sells the coat for $72.00 each. What percent of the purchase price is

the sale price?
Mathematics
2 answers:
vlada-n [284]3 years ago
8 0

Answer:

I believe it's 80%, not sure, but type in 72*60% or 72*0.6.

Step-by-step explanation:

valkas [14]3 years ago
5 0

Answer:

The sale price of the coats is 160% of the purchase price of the coats.

Step-by-step explanation:

The owner buys the coats at a purchase price= $60

He sells the coats for a selling price= $96

Now, the question is:

The selling price $96 is what percentage of the purchase price $60

step 1: 96= x% of 60

step 2: 96= (x/100)*60

step 3: 96= 6x/10

step 4: 960/6 = x

step 5: x = 160%

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58 percent of what is 61.4
Nana76 [90]

Answer:

35.612

Step-by-step explanation:

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3 years ago
If you know the radius, r, of a circle, what do you multiply rby to get the circle's CIRCUMFERENCE?
KengaRu [80]

Answer:

C=2 x pi x radius

Step-by-step explanation:

7 0
3 years ago
Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar
horsena [70]

Answer:

P(A) = \frac{1}{9}

P(B) = \frac{1}{3}

P(C) = \frac{1}{729}

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

P(M) = \frac{1}{3}.

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is P(A) = \frac{1}{9}. We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

So

P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}.

C. If the probability that two people have been hired on a specific day of the week is 3(\frac{1}{3}) ^ 2, then the probability that 7 people have been hired on the same day is:

P(C) = (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7\\\\P(C) = \frac{1}{729}

D. The probability is \frac{1}{729}. This number is quite close to zero. Therefore it is an unlikely bastate event.

6 0
3 years ago
Select the correct answer from each drop-down menu. y = x2 + 2x − 1 y − 3x = 5 The pair of points representing the solution set
katen-ka-za [31]

ANSWER

(-2,-1)

(3,14)

EXPLANATION

The given system is

y =  {x}^{2}  + 2x - 1

y - 3x = 5

or

y = 3x + 5

Equate both of them:

{x}^{2}  + 2x - 1 = 3x + 5

This implies that,

{x}^{2}   - x - 6 = 0

(x - 3)(x + 2) = 0

x=-2 or x=3

When x=-2, y=y=3(-2)+5=-1

(-2,-1) is a solution.

When x=3 , y=3(3)+5=14

(3,14) is also a solution.

7 0
3 years ago
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