So i think what you do is if you make a number line like this:
1...2...3...4...5...6...7...8
you have to find out how many numbers are in between 4 and 7, so I would be 3 because there are 3 numbers I between 4-7.
so
a) 3
b) 6
c) 14
d) 8
Answer:
1.Angle 5
2.Angle 4
3.Angle 6
Step-by-step explanation:
Hey there!
Okay, so when you get a problem like this, all you need to do in insert the given value into the function and solve.
For example:
As you can see, they state that <em>(a) = 27, </em>so you insert 27 in for a in the function and it will look like this:
h(27) = 3(27) + 5
Now you solve on the right side of the equal sign:
3(27) = 81 (you multiply them)
81 + 5 = 86
When you plug the value of 27 in for a in this function, your output is equal to 86.
Z-12=6
you take the 12 and add it to both sides making it look like:
z-12+12=6+12
which also looks like
z-0=6+12
z-0 = z
so now you have
z=6+12
6+12 = 18
SO Z=18!!!
your answer is 18
The least common multiple is 63.
Explanation: 63 is the least number that 3 7 and 9 can go into evenly. Therefore, it is the least common multiple.
