Treat this as you would the quadratic equation x^2 - 4x - 3 + 0. Solve this by completing the square:
x^2 - 4x + 4 - 4 - 7 = 0
(x^2 - 4x + 4) = 11
(x-2)^2 = 11, and so x-2 = plus or minus sqrt(11).
Graph this, using a dashed curve (not a solid curve). Then shade the coordinate plane ABOVE the graph.
Answer:
Step-by-step explanation:
I'm guessing you want the volume?
so for a triangle it's 1/2 base * height for the area
1/2 * 8 * 3 = 12
12*20=240 m^3
Answer:
The answer to the question is
1.5 hours that is;
When the distance between them is more then 135 miles is after 1.5 hours and they will lose radio contact at 3:30 p.m.
Step-by-step explanation:
We note that
The speed of the military convoy headed north =50 mph
The speed of the convoy headed south = 40 mph
Let t be the time taken for the two convoys to be 135 miles apart
The time taken for the two convoys to be 135 miles apart is given by
50×t miles+ 40×t miles= 135 miles
That is 90×t miles = 135 miles
t = 135/90 = 1.5 hrs
We can solve this by using the formula:
(x, y) (x + a, y + b) = (5,-4) (-2,1)
So, plugging in the values and solving for a and b,
5 + a = -2
a = -8
-4 + b = 1
b = 5
Therefore, the translation is
(x,y) (x - 8, y +5)
Suppose
At the same time, we can write
Note that 
(just reverse the sum). Let's pair the first terms of 
and 
, and the second, and the third, and so on:
Now, each grouped term in the sum on the right side adds to 151. There are 52 grouped terms on that same side (because there are 50 numbers in the range of integers 51-100, plus 50 and 101), which menas
But , as we pointed out, so
