Answer: 2 and 3 scoops
Step-by-step explanation:
i guessed :/
Answer:
Example:
A bag contains 3 black balls and 5 white balls. Paul picks a ball at random from the bag and replaces it back in the bag. He mixes the balls in the bag and then picks another ball at random from the bag.
a) Construct a probability tree of the problem.
b) Calculate the probability that Paul picks:
i) two black balls
ii) a black ball in his second draw
Solution:
tree diagram
a) Check that the probabilities in the last column add up to 1.
b) i) To find the probability of getting two black balls, first locate the B branch and then follow the second B branch. Since these are independent events we can multiply the probability of each branch.
ii) There are two outcomes where the second ball can be black.
Either (B, B) or (W, B)
From the probability tree diagram, we get:
P(second ball black)
= P(B, B) or P(W, B)
= P(B, B) + P(W, B)
Here is the answer and steps. Answer:-3/5
Answer:
B
Step-by-step explanation:
17*
Answer:
The attached graph shows my answer.
Step-by-step explanation:
The graph has to start at the top because the number of carrots has to decrease and the graph slants down to the right because the time has to increase. Then the situation says that he eats one carrot at a time until <u>half</u> are eaten. The graph shows the line going down until approximately half. Then he doesn't eat any more, so the line is horizontal until the end of the graph to show no change.
