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3 years ago

Which year is the best prediction for when 1206 people will attend graduate school?

Mathematics

1 answer:

Makovka662 [10]3 years ago

7 0

Answer:

D year 15

Step-by-step explanation:

Given:

y= 8x^2-40x+6

year is the best prediction for when 1206

Finding value of x for y=1206

8x^2-40x+6= 1206

8x^2-40x+6-1206=0

8x^2-40x-1200=0

Solving the above by quadratic formula:

x= $\frac{-b\sqrt{b^{2}-4ac } }{2a}$

= $\frac{40\sqrt{40^{2}-4(8)(-1200) } }{2(8)}$

x= 15 and x= -10

As year can not be negative, hence correct answer is

D: year 15!

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Andrei [34K]

Answer:

Step-by-step explanation:

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3 years ago

Can someone explain the steps to solve number two?

Vlada [557]

Ok so first you would create a proportion.
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3 years ago

Find the point-slope form of the line with the given slope which passes through the indicated slope. Slope = - 8/9 line passes t

kiruha [24]

Y - 8 =(-8/9)(x - 3)

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2 years ago

Read 2 more answers

Two airlines offer special group rates to your school’s Spanish Club for a trip to Mexico City. Mexican Air airline offers a rou

Finger [1]

Answer:

a. The Mexican Airline offers a better deal for 9 students to travel.

b. 10 students

Step-by-step explanation:

a. The Mexican Air airline offers a round trip airfare of $250 per person.

So, for 9 students the fare will be total $(250 × 9) = $2250

Now, the Fiesta airline offers a round trip airfare of $150 per person if the club agrees to pay a one-time group rate processing fee of $1000.

So, for 9 students the total fare will be = $[1000 + (150 × 9)] =$2350.

Therefore, the Mexican Airline offers a better deal for 9 students to travel. (Answer)

b. Let for x students both the airline offers the same total costs.

Then we can write

250x = 1000 + 150x {From the conditions given}

⇒ 100x = 1000

⇒ x = 10

So, if the number of students is 10, then only both the airlines will take same fare. (Answer)

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3 years ago

You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co

alex41 [277]

The perimeter of the rectangular plot of land is given by the expression below

$P=2x+2y$

On the other hand, since the available money to buy fence is D dollars,

$\begin{gathered} D=4(2x)+3(2y) \\ \Rightarrow D=8x+6y \\ D\rightarrow\text{ constant} \end{gathered}$

Furthermore, the area of the enclosed land is given by

$A=xy$

Solving the second equation for x,

$\begin{gathered} D=8x+6y \\ \Rightarrow x=\frac{D-6y}{8} \end{gathered}$

Substituting into the equation for the area,

$\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}$

To find the maximum possible area, solve A'(y)=0, as shown below

$\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}$

Therefore, the corresponding value of x is

$\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}$ <h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2> $\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}$ <h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

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8 months ago