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strojnjashka [21]
4 years ago
9

Please help quickly!

Mathematics
1 answer:
Hunter-Best [27]4 years ago
4 0
You can set up a ratio of side lengths as follows:
\frac{63}{x} = \frac{42}{50}

Now we just solve for x (by cross-multiplying):
63*50 = 42x
x =  \frac{63*50}{42} = 75

So, x = 75 units.
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Lim x—&gt; -2 <br> sqrt(3x+10) -2/ x+2
snow_lady [41]

\displaystyle\lim_{x\to-2}\frac{\sqrt{3x+10}-2}{x+2}

Rationalize the numerator:

\dfrac{\sqrt{3x+10}-2}{x+2}\cdot\dfrac{\sqrt{3x+10}+2}{\sqrt{3x+10}+2}=\dfrac{(3x+10)-4}{(x+2)(\sqrt{3x+10}+2)}=\dfrac3{\sqrt{3x+10}+2}

where the x+2 factors in the numerator and denominator cancel. Then the limit is

\displaystyle\lim_{x\to-2}\frac{\sqrt{3x+10}-2}{x+2}=\lim_{x\to-2}\frac3{\sqrt{3x+10}+2}=\frac3{\sqrt4+2}=\boxed{\frac34}

8 0
3 years ago
Given that U is the midpoint of ON, and V is the midpoint of T'N, select all statements
Mademuasel [1]

Answer:

A,B,C,E

Step-by-step explanation:

7 0
3 years ago
Plz help me I dont understand
Cerrena [4.2K]

Answer:  the answer is -7/5

6 0
3 years ago
Read 2 more answers
Unos tambores, con una etiqueta de 30 L, son llenados con una solución proveniente de una tina grande. Se agrega una cantidad al
Vladimir [108]

A) La probabilidad de que la cantidad total de la solución contenida en 50 tambores sea mayor a 1 500 L es del 50%.

B) La probabilidad de que puedan llenarse 80 tambores sin que se acabe la solución es del 75%.

C) La tina debe contener 2160 litros para que la probabilidad sea 0,9 de que puedan llenarse 80 tambores sin que se acabe la solución.

<h3><u>Desviación estándar</u></h3>

Dado que unos tambores, con una etiqueta de 30 L, son llenados con una solución proveniente de una tina grande, y se agrega una cantidad aleatoriamente de la solución en cada tambor con media de 30.01 L y desviación estándar de 0.1 L, para determinar A) ¿Cuál es la probabilidad de que la cantidad total de la solución contenida en 50 tambores sea mayor a 1 500 L?; B) Si la cantidad total de la solución en la tina es de 2 401 L, ¿cuál es la probabilidad de que puedan llenarse 80 tambores sin que se acabe la solución?; y C) ¿Cuánta solución debe contener la tina para que la probabilidad sea 0,9 de que puedan llenarse 80 tambores sin que se acabe la solución?, se deben realizar los siguientes cálculos:

A)

  • 30.01 - 0.1 = 2.91
  • 30.01 + 0.1 = 3.11
  • 3.11 - 2.91 = 20
  • 3.11 - 3.01 = 10
  • 10 / 20 = 0.5
  • 0.50 = X

B)

  • 2401 / 30.01 = X
  • 79.76 = X
  • 2401 / 30 = X
  • 80 = X
  • (100 + 50) / 2 = 75

C)

  • (80 x 30) x 0.9 = X
  • 2400 x 0.9 = X
  • 2160 = X

Aprende más sobre desviación estándar en brainly.com/question/12402189

3 0
3 years ago
Your model locomotive is 16 inches long. It is an exact model of a locomotive that is 40 feet long. A window on the locomotive i
Rasek [7]
The locomotive is 40 ft long.
40 ft = 40 * 12 in. = 480 in.
The locomotive is 480 inches line.
The model is 16 inches long.
480/16 = 30
The real locomotive is 30 times longer than the model.
A window on the locomotive is 30 times wider than a window on the model.
6 0
3 years ago
Read 2 more answers
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