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kobusy [5.1K]
3 years ago
15

Unos tambores, con una etiqueta de 30 L, son llenados con una solución proveniente de una tina grande. Se agrega una cantidad al

eatoriamente de la solución en cada tambor con media de 30.01 L y desviación estándar de 0.1 L. a) ¿Cuál es la probabilidad de que la cantidad total de la solución contenida en 50 tambores sea mayor a 1 500 L? b) Si la cantidad total de la solución en la tina es de 2 401 L, ¿cuál es la probabilidad de que puedan llenarse 80 tambores sin que se acabe la solución? c) ¿Cuánta solución debe contener la tina para que la probabilidad sea 0,9 de que puedan llenarse 80 tambores sin que se acabe la solución?
Mathematics
1 answer:
Vladimir [108]3 years ago
3 0

A) La probabilidad de que la cantidad total de la solución contenida en 50 tambores sea mayor a 1 500 L es del 50%.

B) La probabilidad de que puedan llenarse 80 tambores sin que se acabe la solución es del 75%.

C) La tina debe contener 2160 litros para que la probabilidad sea 0,9 de que puedan llenarse 80 tambores sin que se acabe la solución.

<h3><u>Desviación estándar</u></h3>

Dado que unos tambores, con una etiqueta de 30 L, son llenados con una solución proveniente de una tina grande, y se agrega una cantidad aleatoriamente de la solución en cada tambor con media de 30.01 L y desviación estándar de 0.1 L, para determinar A) ¿Cuál es la probabilidad de que la cantidad total de la solución contenida en 50 tambores sea mayor a 1 500 L?; B) Si la cantidad total de la solución en la tina es de 2 401 L, ¿cuál es la probabilidad de que puedan llenarse 80 tambores sin que se acabe la solución?; y C) ¿Cuánta solución debe contener la tina para que la probabilidad sea 0,9 de que puedan llenarse 80 tambores sin que se acabe la solución?, se deben realizar los siguientes cálculos:

A)

  • 30.01 - 0.1 = 2.91
  • 30.01 + 0.1 = 3.11
  • 3.11 - 2.91 = 20
  • 3.11 - 3.01 = 10
  • 10 / 20 = 0.5
  • 0.50 = X

B)

  • 2401 / 30.01 = X
  • 79.76 = X
  • 2401 / 30 = X
  • 80 = X
  • (100 + 50) / 2 = 75

C)

  • (80 x 30) x 0.9 = X
  • 2400 x 0.9 = X
  • 2160 = X

Aprende más sobre desviación estándar en brainly.com/question/12402189

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Step-by-step explanation:

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Short way (sometimes it works!)

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