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Roman55 [17]
3 years ago
7

How do you do this question?

Mathematics
1 answer:
madam [21]3 years ago
8 0

Answer:

20

Step-by-step explanation:

A left Riemann sum approximates a definite integral as:

\int\limits^b_a {f(x)} \, dx \approx \sum\limits_{k=1}^{n}f(x_{k}) \Delta x \\where\ \Delta x = \frac{b-a}{n} \ and\ x_{k}=a+\Delta x \times (k-1)

Here, the integral is ∫₀² 9ˣ dx, and the number of subintervals is n = 4.

So Δx = 2/n = 1/2, and x = 2(k−1)/n = (k−1)/2.

Plugging in:

∑₁⁴ 9^((k−1)/2) (1/2)

1/2 ∑₁⁴ 9^((k−1)/2)

1/2 (9^((1−1)/2) + 9^((2−1)/2) + 9^((3−1)/2) + 9^((4−1)/2))

1/2 (9^(0) + 9^(1/2) + 9^(1) + 9^(3/2))

1/2 (1 + 3 + 9 + 27)

20

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Temka [501]

Answer:

neither of those are obtuse angles. the "must include a 90 angle" is the right triangle. the "has at least 2 equal side" is an equilateral triangle

7 0
4 years ago
A: (-5, -5), B: (-1, 3), C: (5, -1)
natka813 [3]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Next consider what happens when two of these functions are composed. Suppose g identifies ng regions of (0, 1)d onto (0, 1)d and
irina [24]

n^{2}fg is regions of f ◦ g(·).

<u>Step-by-step explanation:</u>

When you multiply two functions together, you'll get a third function as the result, and that third function will be the product of the two original functions.

For example, if you multiply f(x) and g(x), their product will be h(x)=f.g(x), or h(x)=f(x)g(x).

Here we have two functions, f identifies n f regions of (0, 1)d onto (0, 1)d which is equivalent to f(x) = n f. And, g identifies n g regions of (0, 1)d onto (0, 1)d which is equivalent to g(x)= n g. Now,

⇒ ( f × g ) (x ) = f(x) × g(x)

⇒( fg )(x) = f(x).g(x)\\( fg )(x) = nf.ng\\(fg)(x) = n^{2}fg

Therefore, n^{2}fg is regions of f ◦ g(·).

8 0
4 years ago
Find a formula for the inverse of the function. f(x) = e^6x − 9
STatiana [176]

Answer:

f^{-1}(x)=\frac{1}{6}\ln(x+9)

Step-by-step explanation:

So we have the function:

f(x)=e^{6x}-9

To solve for the inverse of a function, change f(x) and x, change the f(x) to f⁻¹(x), and solve for it. Therefore:

x=e^{6f^{-1}(x)}-9

Add 9 to both sides:

x+9=e^{6f^{-1}(x)}

Take the natural log of both sides:

\ln(x+9)=\ln(e^{6f^{-1}(x)})

The right side cancels:

\ln(x+9)=6f^{-1}(x)

Divide both sides by 6:

f^{-1}(x)=\frac{1}{6}\ln(x+9)

And we're done!

7 0
3 years ago
Use Cramers Rule to solve the system <br> 2x - 3y = 11<br> -6x + 8y = 34
Nastasia [14]

Step-by-step explanation:

given :

2x - 3y = 11

-6x + 8y = 34

find : the solutions of the system by using Cramers Rule.

solutions:

in the matrix 2x2 form =>

[ 2 -3] [x] [11]

=

[-6 8] [ y] [34]

D =

| 2 -3 |

|-6 8 |

= 8×2 - (-3) (-6)

= 16-18 = -2

Dx = | 11 -3 |

| 34 8 |

= 11×8 - (-3) (34)

= 88 + 102

= 190

Dy = | 2 11 |

|-6 34 |

= 2×34 - (-6) (11)

= 68 + 66

= 134

x = Dx/D = 190/-2 = -95

y = Dy/D = 134/-2 = -67

the solutions = {-95, -67}

8 0
3 years ago
Read 2 more answers
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