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Fiesta28 [93]
3 years ago
7

Find missing number from letter n ! Please

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
5 0

Answer:

1. n= 20 /13

2. n=10

3. n=35

4. n=9

That's all I could do, I got tired of typing lol

Step-by-step explanation:

1.  4/n=13/5 we cross multiply, (4)*(5)=13*n, 20=13n Flip the equation.  13n=20, divide 13 on both sides, 13n/13=20/13, n= 20 /13

2. 9/6= 15/n, we cross multiply 9*n=(15)*(6), 9n=90, Divide both sides by 9. 9n/9=90/9 n=10

3. 28/4=n/5 Cross-multiply, (28)*(5)=n*(4), 140=4n Flip the equation.4n=140 Divide both sides by 4. 4n/4=140/4 n=35

4. n/6=6/4 we cross multiply,n*(4)=(6)*(6), 4n=36, Divide both sides by 4 4n/4=36/4.  n=9

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Answer:

23 is the answer of the question

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3 years ago
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The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth
Art [367]

Answer:

a) N_0=250\; k=0.15

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies t=0. And N(0)=N_0. The process is:

N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250

b) After 2 days means t=48. So, we just replace and operate:

N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}

c) N(t_1)=4000; \;t_1=?

N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\  \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h

d) t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)

N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h

6 0
3 years ago
Help, how would I get my answer for this question?
Maslowich

Answer:

(-4,32)

Step-by-step explanation:

Given points are (-1,-8)

And given transformation is D_4 r_{x-axis}

We will start from left to right.

First transformation is reflection about x-axis.

When we reflect about x-axis (x,y)\ became\ (x,-y)

So, (-1,-8)=[-1,-(-8)]=(-1,8)

Now next transformation is dilation with a factor 4.

If we do dilation with a factor 'k' to the point (x,y)

New co-ordinates after dilation became (kx,ky)

So, (-1,8)\ became\ (-4,32)

8 0
3 years ago
1. a line with a slope of 1/3 passes through the point (3, 6) . which point also lies on this line?
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1) Substituting into point-slope form, the equation of the line is y-6=⅓(x-3), which rearranges to:

  • y-6 = ⅓x - 1
  • y = ⅓x + 5

So, we can now substitute in the coordinates of each of the options to see which point lies on the line.

  1. 3 = ⅓(6) + 5 -> 3 = 7, which is false.
  2. 6 = ⅓(7) + 5 -> 6 = 22/3, which is false.
  3. -3 = ⅓(-3) + 5 -> -3 = 4, which is false.
  4. 3 = ⅓(-6) + 5 -> 3 = 3, which is true.

So, the answer is (4) (-6, 3)

2) Substituting into point-slope form, the equation of the line is y - 5 = ¾(x-2), which rearranges to:

  • y - 5 = 0.75x - 1.5
  • y = 0.75x + 3.5

So, we can now substitute in the coordinates of each of the options to see which point lies on the line.

  1. 8 = 0.75(6)+3.5 -> 8 = 8, which is true.
  2. 9 = 0.75(5) + 3.5 -> 9 = 7.25, which is false.
  3. 1 = 0.75(-1) + 3.5 -> 1 = 2.75, which is false.
  4. 2 = 0.75(6) + 3.5 -> 2 = 8, which is false.

So, the answer is (1) (6, 8).

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2 years ago
The expression once The left side of an equation is shown below. 3(x+1)+9 if the equation has no solution which expression can b
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<h3>Answer:</h3>

C. 4(x-3)-x

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All of the given expressions are equivalent to 3x+12 except selection C. Using that in your equation makes it be ...

... 3(x +1) +9 = 4(x -3) -x

... 3x +12 = 3x -12

... 12 = -12 . . . . . <em>false</em>

There is no value of x that will make this true, hence NO SOLUTION.

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<em>Comment on the other choices</em>

3x+12 = 3x+12 has an <em>infinite number of solutions</em>, as <u><em>any</em></u> value of x will make this true.

7 0
3 years ago
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