The answer is c. Bcs A + B = 90 [ 35 + 55 = 90]
For each <em>x</em> in the interval 0 ≤ <em>x</em> ≤ 5, the shell at that point has
• radius = 5 - <em>x</em>, which is the distance from <em>x</em> to <em>x</em> = 5
• height = <em>x</em> ² + 2
• thickness = d<em>x</em>
and hence contributes a volume of 2<em>π</em> (5 - <em>x</em>) (<em>x</em> ² + 2) d<em>x</em>.
Taking infinitely many of these shells and summing their volumes (i.e. integrating) gives the volume of the region:

Rewrite and factor 9 and 21;
3•3+3•7= 3(3+7)
GCF for 9 and 21 is 3
Answer:
8k+11
Step-by-step explanation:
Combine like terms
9k-k
7+4
9k-k=8k
7+4=11
8k+11
I forget how to do this. I haven't done this in awhile.