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Sindrei [870]
3 years ago
12

Find the value of b if the following figures are similar.​

Mathematics
2 answers:
Brrunno [24]3 years ago
8 0
B = 15 - (20 - 12)
b = 15 - 8
b = 7
chubhunter [2.5K]3 years ago
3 0

Answer:

7

Step-by-step explanation:

20 - 12 = 8

15 - b = 8

-b = 8 - 15

b = 7 ( -ve signs will become +ve)

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An electronics hobbyist has three electronic parts cabinets with two drawers each.
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Answer:

a) 0.5 = 50% probability that an NPN transistor will be selected.

b) 0.3333 = 33.33% probability that it came from the cabinet that contains both types

c) 66.67% probability that it comes from the cabinet that contains only NPN transistors

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

a) What is the probability that an NPN transistor will be selected?

1/3 probability that the first cabinet is chosen. This cabinet has two transistors, both of which are NPN, so 100% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, both of which are PNP, so 0% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, one of which is NPN, so 50% probability of selecting a NPN transistor.

So

p = \frac{1}{3}*1 + \frac{1}{3}*0 + \frac{1}{3}*0.5 = \frac{1}{3} + \frac{1}{6} = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = 0.5

0.5 = 50% probability that an NPN transistor will be selected.

b) Given that the hobbyist selects an NPN transistor, what is the probability that it came from the cabinet that contains both types?

Here we use the conditional probability formula.

Event A: NPN transistor

Event B: From the third cabinet.

50% probability that an NPN transistor will be selected, so P(A) = 0.5.

1/6 probability that it is from the third cabinet and NPN, so P(A \cap B) = \frac{1}{6}

The desired probability is:

P(B|A) = \frac{\frac{1}{6}}{0.5} = 0.3333

0.3333 = 33.33% probability that it came from the cabinet that contains both types.

c) Given that an NPN transistor is selected what is the probability that it comes from the cabinet that contains only NPN transistors?

Either it comes from the cabinet with only NPN transistors, or it comes from the cabinet with both types of transistors. The sum of the probabilities of these outcomes is 100%. So

x + 33.33 = 100

x = 66.67

66.67% probability that it comes from the cabinet that contains only NPN transistors

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what is the value of the reciprocal of $\frac{-2}{5}$? express your answer as a decimal to the nearest tenth.
olga2289 [7]

The reciprocal of -2/5, expressed as a decimal to the nearest tenth is: -2.5.

<h3>What is the Reciprocal of a Number?</h3>

The reciprocal of a number can be described as the inverse of that number. For example, if a is given as a real number, therefore, the reciprocal of a would be 1/a.

Another example is a/b. The reciprocal of a/b is b/a.

Thus, the reciprocal of -2/5 is -5/2.

Expressing this as a decimal, we would have:

-5/2 = 2.5 (nearest tenth).

Therefore, the reciprocal of -2/5, expressed as a decimal to the nearest tenth is: -2.5.

Learn more about the reciprocal of a number on:

brainly.com/question/20896748

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