An increase in Consumption will ___________ in the Classical Model of Aggregate Demand.

to troubleshoot an output component or input device, the first step is to activate the input device that controls the first outp

Firdavs [7]

to troubleshoot an output component or input device, the first step is to activate the input device that controls the first output component It is TRUE statement.

<h3>What does troubleshooting mean?</h3>

The act of discovering, planning, and resolving a problem, mistake, or malfunction in a software or computer system is known as troubleshooting. When a computer or program becomes broken, unresponsive, or behaves abnormally, it can be repaired and restored.

Troubleshooting is the final stage of a complicated process. In order to be able to talk about something, we must bear that the solution was positive and that the whole problem was not positive. There are many types of conflicts and many ways to resolve them.

Learn more about input and output devices:brainly.com/question/17964714

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Letter Frequency Write a function that will take a string and return a count of each letter in the string. For example, "my dog

Nostrana [21]

Answer:

Check the explanation

Explanation:

Code to copy:

// ConsoleApplication7.cpp : Defines the entry point for the console application.

//

#include "stdafx.h"

#include <iostream>

#include <cstring>

#include <string>

using namespace std;

int * letterFrequency(char s[]);

int main()

{

int *freq_letters;

char *s = new char[100];

freq_letters = new int[26];

//To read the input string in order to find the frequency of each letter

cout << "Enter a string: ";

cin.getline(s, ' ');

//call the function to find the occurrence of each alphabet

freq_letters = letterFrequency(s);

//Display the count

cout << "Letter Frequency " << endl;

for (int i = 0; i < 26; i++)

{

//Constriant to check if the letter appeared at least once in the string and so printing the frequency of its occurence

if (freq_letters[i] != 0)

cout << " " << static_cast<char>(i + 'a') << " " << freq_letters[i] << endl;

}

system("pause");

return 0;

}

//Define the function to find occurrence of each letter in the input string

int * letterFrequency(char s[])

{

int *occurrence_array;

//to store the output of occurrences for each alphabet

occurrence_array = new int[26];

// to store the count of occurrence for each letter temporarily

int letter_count;

// for loop to check the occurrence for all 26 alphabets

for (int i = 0; i < 26; i++)

{

letter_count = 0;

for (int j = 0; j < strlen(s); j++)

{

/*comparing the ascii values of each alphabet with every character from the string by converting it to lower case i.e. case insensitive*/

if (int('a') + i == int(tolower(s[j])))

letter_count++;

}

occurrence_array[i] = letter_count;//To store the count calculated for each alphabet

}

return occurrence_array;

}

The following below code screenshot and output shows that when the string is entered, the output will shows each lettercount irrespective of whether the letter is in capitals or small and does not count non-letter characters (i.e spaces, punctuations etc.)