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masha68 [24]
2 years ago
8

1. Name the three kinds of Eraser in Photoshop. ​

Computers and Technology
2 answers:
antiseptic1488 [7]2 years ago
5 0

Answer:

the Eraser, Background Eraser, and Magic Eraser.

Explanation:

the Eraser, Background Eraser, and Magic Eraser.

Sunny_sXe [5.5K]2 years ago
3 0

Answer:

  • Eraser
  • Background Eraser
  • Magic Eraser.

Explanation:

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Mobile devices have their own OSs, tailored to their handheld needs, which means they are not immune to what?
NikAS [45]

Answer:

Malware

Explanation:

Malware is used in many types of software included handheld OS's

6 0
2 years ago
The angles of a quadrilateral are in the ratio 1:2:3:4 what is the largest angle​
zheka24 [161]

Answer:

144°

Explanation:

The sum of the measures of interior angles of a quadrilateral is 360°

The ratio of angle measures is 1:2:3:4

Total ratio = 1+2+3+4=10

The angles will be :

1/10 * 360°= 36°

2/10*360°=72°

3/10*360°=108°

4/10*360°=144°

The largest angle is 144°

7 0
3 years ago
HELP LOTS OF POINTS
andrew11 [14]

My guess would be B and D.

3 0
3 years ago
Read 2 more answers
This program is to compute and write to a file the GPA for student scores read from an input file. The point values of the grade
VARVARA [1.3K]

Answer:

#Take input from the user

filename=input('Enter name of input file: ')

total_units=0#Total number of units for a student

total_score=0#Total score of a student

#Assign a score to each grade. I have reduced 0.33 for each grade. Change here if you need to

grade={'A':4.0,'A-':3.67,'B+':3.34,'B':3.01,'B-':2.68,'C+':2.35,'C':2.02,'C-':1.69,'D+':1.36,'D':1.03}

try:

with open(filename,"r") as input_file:#Open the file for input(reading)

output_file=open("GPA_output.txt","w") #Create and open GPA_output.txt if it doesn't exist for writing

for student_record in input_file:#read from input file

if("," in student_record):#if there is a , that means this is the student name

student_name=student_record.strip('\n')#Remove \n from student name

continue

else:

if(" " in student_record):#If a line contains spaces then its the student's grades for a course

student=student_record.split(" ")#Split to find the coursename, units and grade

#student[0]=coursename student[1]=units student[2]=grade

total_units+=int(student[1])#Calculate total units for 1 student

total_score+=int(student[1])*grade[student[2].strip('\n')]#Find the total score of a student

#grade[student[2]] will lookup for the score that we initialized earlier

#if student has a grade as A then this will look up as grade['A'] which will return 4

#Find the total score as product of this grade and units for this course

continue

else:

if(total_units>0):#Check if score has been calculated for a student earlier

print("in")

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

if(total_units>0):#Essential for the case when the file doesn't end with a new line(Check if total_units is not 0) which means a record is pending

#to be written to the file

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

input_file.close()#Close the input file

output_file.close()#Close the output file

except IOError as e:

print("Problem in Opening the required file")#Print a message if file cannot be opened

Explanation:

The program has been tested for all 3 scenarios mentioned i.e.

a. If the file ends without \n

b. If the file ends with 2 \n

c. If the file ends with 1 \n

PS: The Program will run irrespective of how it ends. Even if there are many \n at the end of file, the program will be fine.

3 0
3 years ago
Given the following program: public class MysteryNumbers { public static void main(String[] args) { String one = "two"; String t
enyata [817]

Answer:

Check the explanation

Explanation:

/*Given the following program:

public class MysteryNumbers {

   public static void main(String[] args) {

       String one = "two";

       String two = "three";

       String three = "1";

       int number = 20;

​

       sentence(one, two, 3);

       sentence(two, three, 14);

       sentence(three, three, number + 1);

       sentence(three, two, 1);

       sentence("eight", three, number / 2);

   }

​

   public static void sentence(String three, String one, int number) {

       System.out.println(one + " times " + three + " = " + (number * 2));

   }

}*/

Write the output of each of the following calls.

sentence(one, two, 3);     three times two = 6

sentence(two, three, 14); 1 times three = 28

sentence(three, three, number + 1); 1 times 1 = 42

sentence(three, two, 1);   three times 1 = 2

sentence("eight", three, number / 2); 1 times eight = 20

7 0
3 years ago
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