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3 years ago

What is the domain of the inverse of a relation?

2 answers:

7 0

If say a relation has a value pairs of say

(a,b),(c,d),(e,f),(g,h),(i,j)

the the value pairs for its inverse will be

<span>(b,a),(d,c),(f,e),(h,g),(j,i)

notice, is the same pair, but flipped sideways.

and of course, the domain is the set of the x-values or the x-coordinate or the first value of each pair, as you already should know.</span>

GalinKa [24]3 years ago

4 0

The domain is the space between the end points on the x axis
ex: D:-2(<=)x(<=)4 this means that the domain is any numbers between -2 and 4

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Step-by-step explanation:

According to the described rule, we have

$a_1=7\\ \\a_1^2=7^2=49\Rightarrow a_2=4+9+1=14\\ \\a_2^2=14^2=196\Rightarrow a_3=1+9+6+1=17\\ \\a_3^2=17^2=289\Rightarrow a_4=2+8+9+1=20\\ \\a_4^2=20^2=400\Rightarrow a_5=4+0+0+1=5\\ \\a_5^2=5^2=25\Rightarrow a_6=2+5+1=8\\ \\a_6^2=8^2=64\Rightarrow a_7=6+4+1=11\\ \\a_7^2=11^2=121\Rightarrow a_8=1+2+1+1=5\\ \\\text{and so on...}$

We can see the pattern

$a_5=a_8=a_{11}=a_{14}=...=5\\ \\a_6=a_9=a_{12}=a_{15}=...=8\\ \\a_7=a_{10}=a_{13}=a_{16}=...=11$

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$a_{3k-1}=5\\ \\a_{3k}=8\\ \\a_{3k+1}=11$

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