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miss Akunina [59]
3 years ago
6

can someone please help? If you could Atleast explain question 1 and 4 that would help. but preferably ig someone could awnser a

nd explain all the questions ​

Mathematics
2 answers:
AURORKA [14]3 years ago
6 0

Answer:

1)7*3

4)m^2

Step-by-step explanation:

The first four problems deal with the area of the rectangle, or length times width(7*3,m*m=m^2).

The last four problems are dealing with adding areas. Find the area of the two rectangles(length times width), then add them together to find the total area.

Triss [41]3 years ago
4 0

Answer:

Area = Base • Height

1) 3 • 7

2) 4 • a

3) m^{2}

4) 4(x + 1) = 4x + 4

5) 7(d + 4) = 7d + 28

6) y(y + 3) = y^{2} + 3y

Step-by-step explanation:

They are asking for an expression. An expression is made up of terms, variables, and an operation. They do not contain equal signs.

For questions 4 through 6, they want you to use the distributive property. There is no way of solving them without having either the length of both sides or the total area.

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Please help
MrRa [10]

Answer:

About 99.7% of births would be expected to occur within 51 days of the mean pregnancy​ length

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Standard deviation = 17.

About what percentage of births would be expected to occur within 51 days of the mean pregnancy​ length?

51/17 = 3.

So, within 3 standard deviations of the mean.

About 99.7% of births would be expected to occur within 51 days of the mean pregnancy​ length

4 0
3 years ago
Kilometers Walked for Charity
masha68 [24]

Answer:what’s the lowest value?

what’s the highest value?

there is your range

Step-by-step explanation:

3 0
3 years ago
Pedro bought lb of red sand and lb of brown sand to refill his sand box. Both types of sand cost $4.60 a pound. How much did Ped
Doss [256]
If we know that Pedro bought 1 \frac{1}{4} pounds of red sand, and 5 \frac{1}{2} pounds of brown sand, and they both cost $4.60, then we just have to add the individual amounts of sand, since they cost the same.

1  \frac{1}{4} + 5  \frac{1}{2} = 6  \frac{3}{4}

So Pedro bought 6 \frac{3}{4} lbs of sand overall. Now, we just need to multiply the cost per pound by the total amount of sand he bought.

6 \frac{3}{4} * 4.6 = 31.05

Pedro spent $31.05 on sand, which is answer choice B.
Hope that helped =)
4 0
4 years ago
Read 2 more answers
Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho
Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10

P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]

As, P(z>1.28)=0.10  [By z-table]

Then,

\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0
4 years ago
HELPPPPPPP!!!!! ASAPPPPPP!!!!
Xelga [282]

Answer: I think your answer would be B

i hope it's right

4 0
3 years ago
Read 2 more answers
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