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yan [13]
3 years ago
8

Justin, Cam, and Ben are playing a board game where exactly one player will win. Ben estimates that Justin has a 20\%20%20, perc

ent chance of winning each game, and that Cam has a 50\%50%50, percent chance of winning each game.
If Justin, Cam, and Ben were to play the board game 200200200 times, which of the following is the best prediction for the number of times that Ben would win the board game?
Choose 1 answer:
Choose 1 answer:

A
303030

B
454545

C
606060

D
757
Mathematics
1 answer:
Alex Ar [27]3 years ago
8 0

Answer:

<u>The correct answer is C. 60.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Justin percent chance of winning each game = 20%

Cam percent chance of winning each game = 50%

Ben percent chance of winning each game = 100 - 50 - 20 = 30%

2. If Justin, Cam, and Ben were to play the board game 200 times, which of the following is the best prediction for the number of times that Ben would win the board game?

Number of times Ben would win the board game = Ben percent chance of winning each game * Number of times Justin, Cam and Ben were to play the board game

Replacing with the values we have:

Number of times Ben would win the board game = 30% * 200

Number of times Ben would win the board game = 0.30 * 200 = 60

<u>The correct answer is C. 60.</u>

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