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4 years ago

Make up two equations, one that is true and one that is false. do not state which equation is true and which is false.

Mathematics

1 answer:

Sophie [7]4 years ago

4 0

3 + 6 = 9 - <span>1
4x3=36/3</span>

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In a study of births from New York State, data were collected from 4 hospitals and coded as follows: (1) Albany Medical Center (

nalin [4]

Answer:

No. See the explanation below.

Step-by-step explanation:

No makes sense.

For this case the codification used is just a notation to identify the hospital. No matter if the code is a numerical value not makes sense calculate the average for these numbers since that not represent any statistic useful for the study.

And the other reason why is not appropiate calculate the mean of these numbers is that if we calculate the mean we don't have a maning for this number since we can't say the mean for the codes is (a number) since that's irrrelevant for the study.

4 0

3 years ago

3(x-1) - 8 = 4(1+x) +5

juin [17]

Answer:

x=-20

Step-by-step explanation:

3x-11=4x+9

3x=4x+20

x+20=0

x=-20

8 0

3 years ago

Read 2 more answers

Determine the value of x in the figure.

asambeis [7]

You have to show the figure lol

4 0

3 years ago

7x - 20 = 2x - 3(3x + 2)

olga nikolaevna [1]

Answer:

x=1

Step-by-step explanation:

7x - 20 = 2x - 3(3x + 2)

Distribute

7x -20 = 2x -9x -6

Combine like terms

7x-20 =-7x -6

Add 7x to each side

7x+7x-20 =-7x+7x -6

14x -20 = -6

Add 20 to each side

14x-20+20 =-6+20

14x = 14

Divide by 14

14x/14=14/14

x=1

6 0

3 years ago

Read 2 more answers

.. Which of the following are the coordinates of the vertices of the following square with sides of length a?

atroni [7]

Option A: $O(0,0), S(0,a), T(a,a), W(a,0)$

Option D: $O(0,0), S(a,0), T(a,a), W(0,a)$

Step-by-step explanation:

Option A: $O(0,0), S(0,a), T(a,a), W(a,0)$

To find the sides of a square, let us use the distance formula,

$d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Now, we shall find the length of the square,

$\begin{array}{l}{\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } S T=\sqrt{(a-0)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } T W=\sqrt{(a-a)^{2}+(0-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a}\end{array}$

Thus, the square with vertices $O(0,0), S(0,a), T(a,a), W(a,0)$ has sides of length a.

Option B: $O(0,0), S(0,a), T(2a,2a), W(a,0)$

Now, we shall find the length of the square,

$\begin{aligned}&\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text {Length } S T=\sqrt{(2 a-0)^{2}+(2 a-a)^{2}}=\sqrt{5 a^{2}}=a \sqrt{5}\\&\text {Length } T W=\sqrt{(a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{2 a^{2}}=a \sqrt{2}\\&\text {Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}$

This is not a square because the lengths are not equal.

Option C: $O(0,0), S(0,2a), T(2a,2a), W(2a,0)$

Now, we shall find the length of the square,

$\begin{array}{l}{\text { Length OS }=\sqrt{(0-0)^{2}+(2 a-0)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } S T=\sqrt{(2 a-0)^{2}+(2 a-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } T W=\sqrt{(2 a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } O W=\sqrt{(2 a-0)^{2}+(0-0)^{2}}=\sqrt{4 a^{2}}=2 a}\end{array}$

Thus, the square with vertices $O(0,0), S(0,2a), T(2a,2a), W(2a,0)$ has sides of length 2a.

Option D: $O(0,0), S(a,0), T(a,a), W(0,a)$

Now, we shall find the length of the square,

$\begin{aligned}&\text { Length OS }=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } S T=\sqrt{(a-a)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } T W=\sqrt{(0-a)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } O W=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}$

Thus, the square with vertices $O(0,0), S(a,0), T(a,a), W(0,a)$ has sides of length a.

Thus, the correct answers are option a and option d.

8 0

3 years ago