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3 years ago

Is 4 and 4 perpendicular

Mathematics

1 answer:

viva [34]3 years ago

5 0

Answer:

No.

Step-by-step explanation:

Because perpendicular means negative reciprocal of the slope. So 4 and -1/4 are perpendicular.

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Simplify (x^-2y^6/x^-4y^8)1/2

AlexFokin [52]

Simplify the following:
(y^6 y^8)/((2 x^2)/(x^4))
Combine powers. (y^6 y^8)/((x^2×2)/x^4) = (y^(8 + 6) x^(4 - 2))/2:
(y^(8 + 6) x^(4 - 2))/2
8 + 6 = 14:
(y^14 x^(4 - 2))/2
4 - 2 = 2:
Answer: (y^14 x^2)/2

6 0

3 years ago

A function is _____ a relation. A) always B) sometimes C) never

VikaD [51]

I believe that; A function is {A) sometimes} a relation.

4 0

2 years ago

Help me... I don't really understand and need an explanation

ehidna [41]

Answer:

x=17

Step-by-step explanation:

This should be for a "kite": AD=DC, AB=BC and ∠A=∠C

8x-27 = 3x+58

5x = 85

x = 17

3 0

2 years ago

Least to greatest 35%, 32/100, 1/3, .305, 3/10

Goryan [66]

Answer: 3/10 , 32/100 , 1/3 , 35% , 305

Step-by-step explanation:

1. Change 3/10 to a decimal

= 0.3

2. change 32/100 to a decimal

=0.32

3. Change 1/3 to a decimal

=0.3

4. Order and Done !

6 0

3 years ago

Read 2 more answers

A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled

klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}$

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

$\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5$

The standard deviation of the sample is calculated as:

$s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8$

Then, we can calculate the standard error of the mean as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5$

6 0

3 years ago