Answer:
= 1.56
Step-by-step explanation:
Hello!
You have two independent samples of fertilizers from distributor A and B, and need to test if the average content of nitrogen from fertilizer distributed by A is greater than the average content of nitrogen from fertilizer distributed by B.
Sample 1
X₁: Content of nitrogen of a fertilizer batch distributed by A
n₁= 4 batches
Sample mean X₁[bar]= 23pound/batch
σ₁= 4 poundes/batch
Sample 2
X₂: Content of nitrogen of a fertilizer batch distributed by B
n₂= 4 batches
Sample mean X₂[bar]= 18pound/batch
σ₂= 5 pounds/batch
Both variables have a normal distribution. Now since you have the information on the variables distribution and the values of the population standard deviations, you could use a pooled Z-test.
Your hypothesis are:
H₀: μ₁ ≤ μ₂
H₁: μ₁ > μ₂
The statistic to use is:
Z= <u> X₁[bar] - X₂[bar] - (μ₁ - μ₂) </u>~N(0;1)
√(δ²₁/n₁ + δ²₂/n₂)
=<u> </u>(<u>23 - 18) - 0 </u> = 1.56
√(16/4 + 25/4)
I hope this helps!
Answer:
Step-by-step explanation:
Given that a study was conducted to find out if a new exercise program was more effective than an old one at improving cardiovascular fitness.
Subjects were randomly selected to participate and then randomly assigned to one of the two programs. After six months of exercising, they were given a score based on their fitness performance. Scores ranged from 19 to 73, with higher scores indicating higher performance.
Here there are two groups one for each program. After recording the scores groupwise, mean, std deviation of each group to be calculated.
Then independent sample test (option B) to be done.
Paired data set is not right because same person cannot be in two programs.
Here proportion is not recorded so D is wrong. Since variance is not checked anova is not right. Independence is not checked so E is wrong. Regression is wrong because there is no estimate for regression line here
B) is right.
Answer:
y = 2/3x -2
Step-by-step explanation:
The slope intercept form of a line is
y = mx+b where m is the slope and b is the y intercept
3y -2x = -6
Solve for y
Add 2x to each side
3y = 2x-6
Divide by 3
3y/3 = 2x/3 -6/3
y = 2/3x -2
Step-by-step explanation:
The degree of an algebraic expression is the largest exponent of the variable present. In expressions with multiple variables, the exponents of each variables are added.
First Expression;
pq: Degree = 1 + 1 = 2
p²q: Degree = 2 + 1 = 3
p²q²: Degree = 2 + 2 = 4
The degree of this expression is 4
Second Expression;
2y²z: Degree = 2 + 1 = 3
10yz: Degree = 1 + 1 = 2
The degree of this expression is 3