Answer:
2x^3−7x^2+16x−15
Step-by-step explanation:
(2x−3)(x^2−2x+5)
=(2x+−3)(x^2+−2x+5)
=(2x)(x^2)+(2x)(−2x)+(2x)(5)+(−3)(x^2)+(−3)(−2x)+(−3)(5)
=2x^3−4x^2+10x−3x^2+6x−15
=2x3−7x2+16x−15
Answer:
Sorry, I can't type well.
<h2>I think it's <u>false</u></h2>
<h2><u><em>I</em><em> </em><em>hope</em><em> </em><em>it's</em><em> </em><em>helpfull </em><em>for</em><em> you</em></u></h2>
The inequalities that are given in this item are given below,
y < 5x - 1
y ≥ -3x +4
We dropped the inequalities sign to solve for the values of x and y for the intersection.
y = 5x - 1
y = 3x + 4
Substituting the y from the first equation to the y of the second equation,
5x - 1 = 3x + 4
2x = 5
x = 5/2
Substituting for y,
y = (5)(5/2) - 1
y = 25/2 - 1 = 11.5
The intersection is (5/2, 11.5)
The solutions of the system of inequalities lie in the 3rd and 4th quadrants.
Answer:
Wrong Question
Step-by-step explanation:
You should write of what context is this question. Else wise the question will be wrong.
This doesn't follow mathematical arithmetic rule at all.
