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lidiya [134]
3 years ago
15

Factorise 5x^2 - 34x + 24

Mathematics
1 answer:
kvv77 [185]3 years ago
7 0
Factor by grouping
<span> 5x^2 - 34x + 24
= (x-6)(5x-4)</span>
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If f(x) = 7 + 4x and g(x)=1/2x, what is the value of (f/g)(5)?
Anestetic [448]
f(x)=7+4x;\ g(x)=\dfrac{1}{2}x\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}=\dfrac{7+4x}{\frac{1}{2}x}=\dfrac{2(7+4x)}{x}=\dfrac{14+8x}{x}\\\\\left(\dfrac{f}{g}\right)(5)=\dfrac{f(5)}{g(5)}=\dfrac{14+8\cdot5}{5}=\dfrac{14+40}{5}=\dfrac{54}{5}=10.8
8 0
2 years ago
Read 2 more answers
How do I subtract decimals from whole numbers?
Gekata [30.6K]

Answer:

Just use long subtraction by expanding the decimal places of the whole number. This is done by adding a point, and enough zeros to it to match the number of decimal digits in the other number (digits after the decimal point).

12345678

i.e: 5 - 2.48374827, 2.48374827 has 8 decimal digits, so add 8 zeros after the point.

=

1 1 1 1 1 1 1

5.00000000

-

2.48374827

_______________

2.51625173

7 + 3 = <u>1</u>0, 7 + 2 + <u>1</u> = <u>1</u>0, 8 + 1 + <u>1</u>= <u>1</u>0, 5 + 4 + <u>1</u> = <u>1</u>0, 2 + 7 + <u>1</u> = <u>1</u>0, 3 + 6 + <u>1</u> = <u>1</u>0, 1 + 8 + <u>1</u> = <u>1</u>0, 5 + 4 + <u>1</u> = <u>1</u>0, 2 + 2 + <u>1</u> = <u>5</u><u> </u><u>:</u><u> </u>5.00000000

This is basically borrowing a group of 10s which are the same as 1s in the next decimal place up.

For each digit except the first to the right, let 10 subtract that number from it and minus 1 since the 1 is carried over.

7 0
3 years ago
)) Evaluate the expression for b = 7.<br> 11b - 75 =
Wewaii [24]

Answer:

The answer is 2.

Step-by-step explanation:

11(7) - 75

77-75

=2

7 0
3 years ago
BUILDING ON THE ESSENTIAL QUESTION .<br>How are negative exponents and positive exponents related?
Trava [24]
Zero-Exponent Rule: a0 = 1, this says that anything raised to the zero power is 1. ... Negative Exponent Rule: , this says that negative exponents in the numerator get moved to the denominator and become positive exponents. Negative exponents in the denominator get moved to the numerator and become positive exponents.
5 0
2 years ago
The average hourly wage of computer programmers with 2 years of experience has been $21.80.Because of high demand for computer p
svp [43]

Answer:

d. H0: μ <= 21.80 Ha: μ > 21.80

Step-by-step explanation:

We set the null hypothesis as what is already given . We are already informed that the average wage is equal to  μ <= 21.80 against the claim that is required. It is required to test whether the average wage of the computer programmers is greater than μ > 21.80

So option d is the best answer.

Hypotheses testing is done  using an observation and a claim. The observation is set as a null hypothesis and claim is set as an alternative hypothesis. The null and alternative hypotheses must be chosen wisely to get the correct results.

The critical region is dependent on the claim set.

5 0
3 years ago
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