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Veseljchak [2.6K]
3 years ago
12

Fred's frog jump seven times as far as sells frog the two frogs jump a total of 56 inches how far did Fred's frog jump

Mathematics
1 answer:
hodyreva [135]3 years ago
7 0
Fred's Frog jumped 49 inches
7x + x = 56
8x = 56
x = 7 
Fred's Frog = 7x = 7*7 =49
Hope that helped :D

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a scuba diver descended at a rate of 2 1/4 per second. If 0 represents the surface of the water and distances below the surface
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Answer:

The location will be at - 28\frac{1}{8} units.

Step-by-step explanation:

A scuba diver descended at a rate of 2\frac{1}{4} units per second.

Now, if 0 represents the surface of the water and distances below the surface are negative, then after 12\frac{1}{2} seconds the location of the diver will be given by the followings :

In one second the diver descends by 2.25 units depth.

So, in 12.5 seconds the diver will descend by (2.25 \times 12.5) = 28.125 units i.e. 28\frac{1}{8} units depth.

Therefore, the location will be at - 28\frac{1}{8} units. (Answer)

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The perimeter of the regular polygon is 70 inches

<h3>How to determine the perimeter of the regular polygon?</h3>

The sides of the regular polygon is given as:

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Read more about perimeter at

brainly.com/question/24571594

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3 years ago
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