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Kay [80]
2 years ago
14

Which equation represents a nonproportional relationship?

Mathematics
2 answers:
Liono4ka [1.6K]2 years ago
6 0
The answer will be B
Airida [17]2 years ago
6 0

Answer:

the correct answer is C.) y=3x+5

Step-by-step explanation:

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Please help! Find the area and the perimeter of the shaded regions below. Give your answer as a completely simplified exact valu
Nadya [2.5K]

Answer:

The \ area \ of \ the \ figure = 4\dfrac{1}{2} \cdot \pi + 18 \ cm^2

Step-by-step explanation:

Given that the figure is made up of portion of a square and a semicircle, we have;

BC ≅ AB = 6 cm

The area of semicircle BC with radius BC/2 = 3 is 1/2×π×r² = 1/2×π×3² = 4.5·π cm²

Triangle ABC = 1/2 × Area of square  from which ABC is cut

The area of triangle ABC = 1/2×Base ×Height = 1/2×AB×BC = 1/2×6×6 = 18 cm²

The area of the figure = The area of semicircle BC + The area of triangle ABC

The area of the figure = 4.5·π cm² + 18 cm² = \dfrac{9 \cdot \pi +36}{2} \ cm^2.

5 0
3 years ago
(8x + 11) - (7x - 5)?​
zaharov [31]

Answer:

use the cymath calculator

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Two number cubes are rolled. What is the probability that the sum of the numbers rolled is either 3 or 9?. A.1/6. B.1/13. C.1/18
Elis [28]
So 6 times 6 is 36 so 36 possibilities and the number that add up to 3 or nine are (2,1; 3,6; 4,5;) so 3 out of 36 or 1 out of 12, the answer is not there
3 0
3 years ago
Which of the following is the correct factorization of the
Helga [31]

Answer:

The answer is b

Step-by-step explanation:

(4x+5)(16^2-20x+25)

3 0
3 years ago
How to find function definition area
insens350 [35]

Answer:Definition area"? Do you mean the "natural domain" of the function- the region in which the formula is defined? In order that a number have a square root that number must be non-zero.

Step-by-step explanation:Here, we must have x−1x≥0.

If x is positive, multiplying both sides by x we have x2−1=(x−1)(x+1)≥0. In order for that to be true, both x- 1 and x+ 1 must have the same sign: either x-1> 0 and x+ 1> 0 or x- 1< 0 and x+ 1< 0. The first pair of inequalities is true for x> 1 and the second for x< -1. Since "x is positive", we must have x> 1.

If x is negative, multiplying both sides by x we have x2−1=(x−1)(x+1)≥0. In order for that to be true, x- 1 and x+ 1 must have opposite signs: x+ 1> 0 and x- 1< 0 or x- 1<0 and x- 1> 0. The first pair is true for −1≤0≤1. The second pair are never both true. Since "x is negative" we must have −1≤x≤0.

Of course, we also cannot divide by 0 so x= 0 is not in the domain. The domain is the union of the two separate sets:{x|−1≤x<0}∪{x|x>1}.

Hope That Helps!

8 0
3 years ago
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